BMmMakakakakamkaksdkdkdkfjdnhehyuehehejehehheheyeyeuudjeje
Answer:
16. x = 3.0822, -3.0822
17. x = 1.6432, -1.6432
18. x = 1, -1
Step-by-step explanation:
16. log5[(4x²+2)/8] = 1
(4x²+2)/8 = 5¹
4x² + 2 = 40
4x² = 38
x² = 38/4
x² = 19/2
x = +/- sqrt(19/2)
x = 3.0822, -3.0822
17. log7[(2x²-4)(5)] = 1
10x² - 20 = 7¹
10x² = 27
x² = 2.7
x = +/- sqrt(2.7)
x = 1.6432, -1.6432
18. log5[(2x²+8)/2] = 1
x² + 4 = 5¹
x² = 1
x = +/-1
9514 1404 393
Answer:
the scale drawing is larger
Step-by-step explanation:
The scale tells you that ...
17 cm on the scale drawing represent 1 mm on the actual object.
17 cm is larger than 1 mm, so the scale drawing is larger.
Using conditional probability, it is found that there is a 0.7873 = 78.73% probability that Mona was justifiably dropped.
Conditional Probability
In which
- P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
- P(A) is the probability of A happening.
In this problem:
- Event A: Fail the test.
- Event B: Unfit.
The probability of <u>failing the test</u> is composed by:
- 46% of 37%(are fit).
- 100% of 63%(not fit).
Hence:

The probability of both failing the test and being unfit is:

Hence, the conditional probability is:

0.7873 = 78.73% probability that Mona was justifiably dropped.
A similar problem is given at brainly.com/question/14398287
I'm pretty sure its c.........