Someone help me please

Mathematics

1 answer:

Valentin [98]3 years ago

7 0

Answer:

$1. a_{n} =2n+2\\2. a_{n}=6n+6\\3. a_{n}=4n+4\\4. a_{n}=2n-2\\5. 512 (*2)\\6. 314,928 (*-3)\\7. -65536 (*4)\\8. 917,504 (*4)\\9. -274 (-9)\\10. -230 (-6)\\11. -189 (-5)\\12. 371 (+20)$

Step-by-step explanation:

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Flura [38]

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3 years ago

What is the vertex of the quadratic equation y = - 1/3 (x + 2)^2 +5

Wewaii [24]

Answer:

Step-by-step explanation:

$\text{The vertex form of a quadratic equation:}\\\\y=a(x-h)^2+k\\\\(h,\ k)-vertex\\---------------\\\text{We have:}\\\\y=-\dfrac{1}{3}(x+2)^2+5=-\dfrac{1}{3}(x-(-2))^2+5\Rightarrow h=-2\ \text{and}\ k=5\\\\\text{therefore the vertex is:}\ (-2,\ 5)$

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3 years ago

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth 5y^2-8y=2

solmaris [256]

Answer:

Step-by-step explanation:

First, rewrite the equation (all terms should be in the left side):

$5y^2-8y-2=0.$

In this equation,

$a=5;$
$b=-8;$
$c=-2.$

Then the discriminant

$D=b^2 -4ac=(-8)^2-4\cdot 5\cdot (-2)=64+40=104.$

Then

$y_1=\dfrac{-b+\sqrt{D}}{2a}=\dfrac{-(-8)+\sqrt{104}}{2\cdot 5}=\dfrac{8+2\sqrt{26}}{10}=\dfrac{4+\sqrt{26}}{5},\\ \\y_2=\dfrac{-b-\sqrt{D}}{2a}=\dfrac{-(-8)-\sqrt{104}}{2\cdot 5}=\dfrac{8-2\sqrt{26}}{10}=\dfrac{4-\sqrt{26}}{5}.$