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Kaylis [27]
3 years ago
5

What happens if you try to compile and run this program?

Computers and Technology
1 answer:
Lynna [10]3 years ago
7 0

Your question is poorly formatted

<em>#include <stdio.h> </em>

<em>int main(void) { </em>

<em>int i, t[4]; </em>

<em>t[3] = 0; </em>

<em>for (i = 1; i >= 0; i--) </em>

<em>t[i] = t[3] * i; </em>

<em>printf("%d", +t[1]); </em>

<em>return 0; </em>

<em>}</em>

Answer:

It outputs 0

Explanation:

I'll start my explanation from the third line

This line declares an integer variable i and an array of 4 elements of type integer

<em>int i, t[4]; </em>

<em />

This line initialize the 3rd index element to 0

<em>t[3] = 0; </em>

<em />

The next two lines is an iteration;

The first line of the iteration iterates the value of i in descending order from 1 to 0

<em>for (i = 1; i >= 0; i--) </em>

<em />

This line of the iteration calculates t[1] as t[3] * i and t[0] as t[3] * i; Since t[3] is 0; both t[1] and t[0] will be 0

<em>t[i] = t[3] * i; </em>

<em />

This line prints t[1] which is 0

<em>printf("%d", +t[1]); </em>

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