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Ugo [173]
2 years ago
6

Goals of the project objectives

Computers and Technology
1 answer:
Kryger [21]2 years ago
8 0

are what you plan to achieve by the end of your project.

Explanation:

This might include deliverables and assets, or more intangible objectives like increasing productivity or motivation. Your project objectives should be attainable, time-bound, specific goals you can measure at the end of your project.

statement that describes the “what” of your project. The tangible and measurable “what”. The “what” that's achievable, realistic, and can be completed within the time allowed. These statements ladder up to the goals of the project, providing stepping stones to project success.

<h3>:) CARRYINGTOLEARN</h3>
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Assuming a computer has a single processor and a single core with no support for parallel execution, explain why running a multi
IRISSAK [1]

Answer:

Explanation:

Before we go deep into this question lets have some brief knowledge on parallel execution, parallel processing and multi tasking.

Parallel Execution : in this two or more tasks or program can be executed parallel or simultaneously.

For example if there are two processors and four programs to be executed then it executes two at a time.

Multi tasking: in this two or more tasks can be performed simultaneously switching between them without exiting any application.

For example we use notepad, word pad, excel sheet, chrome all at a time switching between each other.

Multi Threading: It is splitting up the program into different threads.If the contents in the program are independent on each other then the program can be split into multi threads and can be processed.

Multi threading in multi core or processing unit : In this threads are executed parallel or simultaneously in different processes.

For example if there are two processors then one multi threaded program can execute two threads in two different processors.

Multi threaded program in single core unit : In this, program is multi threaded where as threads cannot execute parallel or simultaneously. they sholud be executed by the same processor. So they should wait in queue

Ex: consider three tasks of 6 secs each and multi threaded each into three threads of two seconds.

Task1 3secs > task2 3secs > task3 3 secs it repeats until each task is completed

Total time taken is 3+3+3+3+3+3+3+3+3 is 18seconds...

If they are executed one by one without multi threading total execution time has no change..

Where as multi threading program has its advantages if different threads are executed at different place..

If one thread executes at network, another at printer and other processor then these three can execute at same time at different processors. Multi threading has its advantages but in single core systems it doesn't affect the performance.

Inter process communication consists of

Information Sharing, message passing, Modularity.

In shared memory inter process communication processes shares the memory between each other.

In message passing communication process communicates like request and replies for information and resources.

Interlocking is due to error in resource sharing and information sharing. It results in system collapse.

Al these process communication is required if there are two or more.processes but in single core it is not much useful and advisable.

In single core there will be a single processor, processing multi threaded program as it can access all the memory contents there will be no problem of process communication. Where as in multi core systems different processes may compete for same memory or resource.

In single core systems inter process communication makes things complex and these complexity is not much useful in any of the improvement in performance.

4 0
3 years ago
Consider an unpipelined or single-stage processor design like the one discussed in slide 6 of lecture 17. At the start of a cycl
pantera1 [17]

Answer:

a. Clock Speed of Processor = 0.5 GHz

b. Cycles per Instruction (CPI) = 1 Clock per Instruction

c. Throughput = 1 billion Instruction per Second

Explanation

Given Data

Time Take to complete the single Cycle = 2000ps = 2000 x 10⁻¹²

To Find

a. Clock Speed of Processor = ?

b. Cycles per Instruction (CPI) = ?

c. Throughput = ?

Solution:

a. Clock Speed of Processor = ?

Clock Speed = 1/Time to complete the cycle

                      = 1/2000 x 10⁻¹²  Hz

                      =  0.0005 x 10¹²  Hz

                      =  0.5 x 10⁹  Hz                             as   10⁹ = 1 Giga   so,

                      = 0.5 GHz

b. Cycles per Instruction (CPI) = ?

It is mentioned that, each instruction should start at the start of the new cycle and completely processed at the end of that cycle so, we can say that Cycles per Instruction (CPI) = 1

for above mentioned processor.

c. Throughput = ?

Throughput = CPI x Clock Speed

where

CPI = 1 cycle per instruction

Clock Speed = 1 billion Instructions per Second

as

Clock Speed = 1 billion Cycles per Second

Throughput = 1 cycle per instruction x 1 billion Cycles per Second

Throughput = 1 billion Instruction per Second

                         

6 0
3 years ago
An exclusion contract A. gives a firm the right to be the exclusive provider of a good in a particular market. B. is a form of e
irina1246 [14]

Answer:

D. All of the above

7 0
2 years ago
Write a program that generates 1,000 random integers between 0 and 9 and displays the count for each number. (Hint: Use a list o
masya89 [10]

Answer:

import random

count0, count1, count2, count3,

count4, count5, count6, count7,

count8, count9, i = [0 for _ in range(11)]

while i < 1000:

   number = random.randint(0,9)

   if number == 0:

       count0 = count0 + 1

   if number == 1:

       count1 = count1 + 1

   if number == 2:

       count2 = count2 + 1

   if number == 3:

       count3 = count3 + 1

   if number == 4:

       count4 = count4 + 1

   if number == 0:

       count5 = count5 + 1

   if number == 6:

       count6 = count6 + 1

   if number == 7:

       count7 = count7 + 1

   if number == 0:

       count8 = count8 + 1

   if number == 9:

       count9 = count9 + 1

   

   i = i+1

print("0's: "+ str(count0) + "\n"+ "1's: "+ str(count1) + "\n"+

"2's: "+ str(count2) + "\n"+ "3's: "+ str(count3) + "\n"+

"4's: "+ str(count4) + "\n"+ "5's: "+ str(count5) + "\n"+

"6's: "+ str(count6) + "\n"+ "7's: "+ str(count7) + "\n"+

"8's: "+ str(count8) + "\n"+ "9's: "+ str(count9) + "\n")

Explanation:

- Initialize variables to hold the count for each number

- Initialize <em>i</em> to control the while loop

- Inside the while loop, check for the numbers and increment the count values when matched.

- Print the result

5 0
2 years ago
You have to write a program that will read a number followed by a series of bit operations from a file and perform the given ope
tatuchka [14]

The program what will read a number followed by a series of bit operations from file and perform the given operations sequentially on the number is given below.

<h3>What is an operation in computer science?</h3>

An operation, in mathematics and computer programming, is an action that is carried out to accomplish a given task.

There are five basic types of computer operations:

  • Inputting,
  • processing,
  • outputting,
  • storing, and
  • controlling.

<h3>What is the requested program above?</h3>

#include <stdio.h>

#include <fcntl.h>

int main(int argc, char *argv[])

{

  int number, n, v, temp;

  char line[25], fun[10];

  FILE *f = fopen(argv[1], "r");

 

  fgets(line, 24, f);

  sscanf(line, "%d", &number);   //reading the number

  while( fgets(line, 24, f) )

   {

      sscanf(line, "%s %d %d", fun, &n, &v); //reading the commands

      switch(fun[0])           //checking which command to run

      {

          case 'g':    temp = 1;

                      temp = temp<<n;   //shifting for getting that bit

                      printf("%d\n",(number&temp)&&1);

                      break;

          case 's':   temp = 1;

                      temp = temp<<n;   //shifting for setting that bit

                      if(!v)

                      {

                          temp = ~temp;

                          number = number & temp;

                      }

                      else

                      {

                          number = number | temp;

                      }

                      printf("%d\n",number);

                      break;

          case 'c':   temp = 1;

                      temp = temp<<n;   //shifting for complimenting that bit

                      number = number ^ temp;   //xor to complement that bit

                      printf("%d\n",number);

                      break;

          default:printf("not defined");

      }

  }

  return 0;

}

Execution and Output:

terminal-> $ gcc -o first first.c

terminal-> $ ./first file1.txt

1

4

6

Learn more about programs at;
brainly.com/question/16397886
#SPJ1

8 0
1 year ago
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