Take the derivative with respect to t

the maximum and minimum values occur when the tangent line is zero so we set the derivative to zero

divide by w

we add sin(wt) to both sides

divide both sides by cos(wt)

OR

(wt)=2(n*pi-arctan(2^0.5))
(wt)=2(n*pi+arctan(2^-0.5))
where n is an integer
the absolute max and min will be

since 2npi is just the period of cos

substituting our second soultion we get

since 2npi is the period

so the maximum value =

minimum value =
Answer:
7.) 18.86m
8.) 15 inches
9.) 32 and 34
10.) 21 and 29
11.) change all the decimals in the equation into fractions.
Step-by-step explanation:
Answer:
The answer to your question is $9.5
Step-by-step explanation:
Data
Large pizza = L
Medium pizza = m
Write equation for both situations
Situation 1 5L + 2m = 81.5
Situation 2 4L + 3m = 78.5
Solve the system of equation by elimination
Multiply situation 1 by -3 and situation 2 by 2
-15L - 6m = -244.5
8L + 6m = 157
-7L = -87.5
Solve for L L = -87.5/-7
L = $12.5
Substitute L in Situation 1 to find m
5(12.5) + 2m = 81.5
62.5 + 2m = 81.5
2m = 81.5 - 62.5
2m = 19
m = 19/2
m = $ 9.5
The prize of a medium pizza is $9.5
The class is weighted as follows:
60% Regular Tests
10% Final Exam
15% Project
15% Homework
The total weighted points possible for the class are as follows:
(100+100+100+100+100)*.6 + 100*.1 + 100*.15 + 100*.15 = 340
To calculate her individual final weighted grade we plug in her scores for each category and complete the following computation:
(92+83+77+84+82)*.6 + 88*.1 + 95*.15 + 77*.15 = 285.4
So her weighted grade percent would be 285.4/340 = 83.9% which is a B.