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Nitella [24]
3 years ago
14

Express the fractions 3/4 ,7/16 and 5/8 with the lowest common denominator

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
4 0
3/4, 7/16, 5/8.....LCD = 16

3/4 = 12/16
7/16
5/8 = 10/16
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What is the answer to this 584,405÷884
I am Lyosha [343]

Theirs your answer 661.091628959

6 0
3 years ago
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What is 1 plus 2 plus 3.... plus 200?
Aneli [31]

Answer:

20100

Step-by-step explanation:

There are 200 numbers in this addition problem. To add this, we can do 1 + 200, 2 + 199, 3 + 198 and so on. All of these pairs have a sum of 201 and since there are 200 / 2 = 100 pairs the answer is 201 * 100 = 20100.

6 0
3 years ago
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I got two more pls answer
polet [3.4K]

Answer:

33.) = 4

34.) = 2

35.) = 6

36.) = 6

37.) = 91

38.) = 35

39.) = 4

40.) = 28

41.) = 18

42.) = (-6)

Step-by-step explanation:

<h3>33.)</h3>

(10 + 6) ÷ [(9 – 5) × (5 – 4)²]

(16) ÷ (4) × (1)²

16/4 = 4

Thus, The answer is 4

<h3>34.)</h3>

(3² × 2) ÷ (5 + 8 – 5 + 1)

(9 × 2) ÷ (9)

18/9 = 2

Thus, The answer is 2

<h3>35.)</h3>

6² ÷ {2 + 5 – [9 – (6 + 2)]}

6² ÷ [2 + 5 – (9 – 8)]

36 ÷ [2 + 5 – (1)]

36 ÷ 7 – 1

36/6 = 6

Thus, The answer is 6

<h3>36.)</h3>

(3 × 3 × 2) ÷ (4 – 1)

18/3 = 6

Thus, The answer is 6

<h3>37.)</h3>

4 × 3 × 10 – 4² – (10 + 3)

120 – 16 – 13

120 – 29 = 91

Thus, The answer is 91

<h3>38.)</h3>

5 × [(22 – 1) × 2] ÷ (8 + 2 – 4)

5 × [(21) × 2] ÷ (6)

5 × 42 ÷ 6

5 × 7 = 35

Thus, The answer is 35

<h3>39.)</h3>

-2 × 4 ÷ [2 + (-4) – (-4)] – 4

-8 ÷ (2 – 4 + 4) – 4

-8 ÷ 2 – 4

-8/-2 = 8/2 = 4

Thus, The answer is 4

<h3>40.)</h3>

-4(-1 + 2) × 4 – 2 + (-1)

-4 × (1) × 4 – 2 – 1

(-4) × (-7) = 28

Thus, The answer is 28

<h3>41.)</h3>

-3 – (-3 × 3) + 6 × 2

-3 – (-9) + 12

-3 + 9 + 12

6 + 12 = 18

Thus, The answer is 18

<h3>42.)</h3>

6 – {3² + [3 × (-1)²]}

6 – [9 + (3 × 1)]

6 – (9 + 3)

6 – 12 = -6

Thus, The answer is (-6)

<u>-TheUnknownScientist 72</u>

7 0
3 years ago
Read 2 more answers
Write functions for each of the following transformations using function notation. Choose a different letter to represent each f
joja [24]

Answer:

1. Translation: g(x) = f(x-a)+b.

2. Reflection around y-axis: h(x) = f(-x)

3. Reflection around x-axis: k(x) = -f(x)

4. Rotation of 90° : R_{90} (x,y)=(-y,x)

5. Rotation of 180° : R_{180} (x,y)=(-x,-y).

6. Rotation of 270° : R_{180} (x,y)=(y,-x).

Step-by-step explanation:

Let us assume that the transformations namely translation, reflection are applied to a function f(x) and the rotation is applied to the point ( x,y ).

So, according to the options:

We know that 'translation moves the image in horizontal and vertical direction'.

1. As we have to translate the function f(x) 'a' units to the right and 'b' units up. So, the new form of the function becomes g(x) = f(x-a)+b.

Further, we know that 'reflection means to flip the image around a line'.

2. As, we have to reflect the function f(x) around y-axis. The new form of the function is h(x) = f(-x).

3. As, we have to reflect the function f(x) around x-axis. The new form of the function is k(x) = -f(x).

Since, 'rotation turns the image around a point to a certain degree'.

4. As, we have to rotate ( x,y ) counter-clockwise to 90° about the origin, the new form of the function is R_{90} (x,y)=(-y,x).

5. As, we have to rotate ( x,y ) counter-clockwise to 180° about the origin, the new form of the function is R_{180} (x,y)=(-x,-y).

6. As, we have to rotate ( x,y ) counter-clockwise to 270° about the origin, the new form of the function is R_{180} (x,y)=(y,-x).

5 0
3 years ago
An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y
aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                               P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average time = 23.92 minutes

             s = sample standard deviation = 6.72 minutes

             n = sample of times = 40

             \mu = population mean assembly time

<em> Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

<u>So, a 98% confidence interval for the population mean, </u>\mu<u> is; </u>

P(-2.426 < t_3_9 < 2.426) = 0.98  {As the critical value of z at 1%  level

                                               of significance are -2.426 & 2.426}  

P(-2.426 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.426) = 0.98

P( -2.426 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

P( \bar X-2.426 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

<u>98% confidence interval for</u> \mu = [ \bar X-2.426 \times {\frac{s}{\sqrt{n} } } , \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ]

                                     = [ 23.92-2.426 \times {\frac{6.72}{\sqrt{40} } } , 23.92+2.426 \times {\frac{6.72}{\sqrt{40} } } ]  

                                    = [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0
3 years ago
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