Answer:
13/3 -3i
Step-by-step explanation:
(3i-2/3)-(6i-5)
Distribute the minus sign
(3i-2/3)-6i+5
Combine like term
-2/3 +5 +3i - 6i
-2/3 +15/3 -3i
13/3 -3i
This is standard form
Answer:
Let the vectors be
a = [0, 1, 2] and
b = [1, -2, 3]
( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.
Let the cross product be another vector c.
To find the cross product (c) of a and b, we have
![\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C0%261%262%5C%5C1%26-2%263%5Cend%7Barray%7D%5Cright%5D)
c = i(3 + 4) - j(0 - 2) + k(0 - 1)
c = 7i + 2j - k
c = [7, 2, -1]
( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:
c / | c |
Where | c | = √ (7)² + (2)² + (-1)² = 3√6
Therefore, the unit vector is
or
[
,
,
]
The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:
[
,
,
]
In conclusion, the two unit vectors are;
[
,
,
]
and
[
,
,
]
<em>Hope this helps!</em>
Answer:
The durations of movies in minutes can only take on integer values from 0 to 60. Therefore, it is a discrete data.
X^4 + 2x^2 - 24
= (x^2 + 6)(x^2 - 4)
= (x^2 + 6)(x - 2)(x + 2)
x^4 - 9x^2 + 18
= (x^2 - 6)(x^2 - 3)
Answer:
A and C
Step-by-step explanation:
for A
QT/RT=ST/QT=QS/QR
There are two QT's in this
so
(QT)^2 = RT * ST
FOR B
there is no RT twice
for C
QR/RT RS/QR
There is a QR twice
so QR^2=RT*RS
FOR D there is no RT twice
(if you have the other answers for this quiz plz give them to me lol)