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Alecsey [184]
3 years ago
12

| 5x -2y | - | 3x | if x = -3 and y = 2

Mathematics
2 answers:
Irina-Kira [14]3 years ago
7 0
|(5)(-3)-(2)(2)|-|(3)(3)|
= 10
Natalka [10]3 years ago
5 0

Answer:

If x = -3 and y = 2, then |5x-2y|-|3x| = 10

Step-by-step explanation:

This is a problem that utilizes both substitution and the order of operations.

|5x-2y|-|3x| = \\|-15-(2)(2)|-|(3)(-3)| =\\ |-15-4|-|(3)(-3)| =\\|-19|-|(3)(-3)| =\\19-|(3)(-3)| =\\19-|-9| =\\19-9 =\\10


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The computer that controls a bank's automatic teller machine crashes a mean of 0.6 times per day. What is the probability that,
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Answer:

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Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Mean of 0.6 times a day

7 day week, so \mu = 7*0.6 = 4.2

What is the probability that, in any seven-day week, the computer will crash less than 3 times? Round your answer to four decimal places.

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-4.2}*(4.2)^{0}}{(0)!} = 0.0150

P(X = 1) = \frac{e^{-4.2}*(4.2)^{1}}{(1)!} = 0.0630

P(X = 2) = \frac{e^{-4.2}*(4.2)^{2}}{(2)!} = 0.1323

So

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0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

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