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n200080 [17]
3 years ago
13

Which three lengths could be the lengths of the sides of a triangle?

Mathematics
1 answer:
faust18 [17]3 years ago
8 0
B. 10 cm, 15 cm, 24 cm
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PLEASE HELP I NEED THIS ASAP<br> Find the vertex of y=x^2-7x+4
Goshia [24]

Answer:

\mathrm{Minimum}\space\left(\frac{7}{2},\:-\frac{33}{4}\right)

Step-by-step explanation:

y=x^2-7x+4\\\mathrm{The\:vertex\:of\:an\:up-down\:facing\:parabola\:of\:the\:form}\:y=ax^2+bx+c\:\mathrm{is}\:x_v=-\frac{b}{2a}\\\mathrm{The\:parabola\:params\:are:}\\a=1,\:b=-7,\:c=4\\x_v=-\frac{b}{2a}\\x_v=-\frac{\left(-7\right)}{2\cdot \:1}\\\mathrm{Simplify}\\x_v=\frac{7}{2}\\\mathrm{Plug\:in}\:\:x_v=\frac{7}{2}\:\mathrm{to\:find\:the}\:y_v\:\mathrm{value}\\y_v=\left(\frac{7}{2}\right)^2-7\cdot \frac{7}{2}+4\\

\mathrm{Simplify\:}\left(\frac{7}{2}\right)^2-7\cdot \frac{7}{2}+4:\quad -\frac{33}{4}\\y_v=-\frac{33}{4}\\Therefore\:the\:parabola\:vertex\:is\\\left(\frac{7}{2},\:-\frac{33}{4}\right)\\\mathrm{If}\:a0,\:\mathrm{then\:the\:vertex\:is\:a\:minimum\:value}\\a=1\\\mathrm{Minimum}\space\left(\frac{7}{2},\:-\frac{33}{4}\right)

6 0
3 years ago
A motorcycle is traveling at a constant speed of 75miles per hour. How many feet does it travel in 7seconds? Remember that 1 mil
Stella [2.4K]

770 feets per 7 seconds


5 0
3 years ago
Write 13/40 as a decimal?
borishaifa [10]
0.325 is the answer. :)

6 0
3 years ago
Read 2 more answers
A Which point is located at (-1.14) 1 OA 74 XB 12 B D D ос OD -114 -1 -1 -12 -1/4 Y 14 12 341 174 с 15. Intro​ (I memed this tim
sukhopar [10]
  • (-1,1-1/4)
  • (-1,1+0.25)
  • (-1,1.25)

Now convert it to mixed fraction

  • 1-1/4=5/4

Present in 2nd quadrant.

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4 0
2 years ago
A shopkeeper sold an article at 20 % discount and made a loss of Rs 90. If he had
melamori03 [73]

Answer:

The cost price of the article is Rs 1050

The marked price of the article Rs 1200

Step-by-step explanation:

The given discount on the article = 20%

The amount loss  = Rs 90

With a discount of 5% the amount gained = Rs 90

Let the cost price of the article = X

Let the marked price of the article = Y

Therefore, we have;

(1 - 0.2) × Y = X - Rs 90

(1 - 0.5) × Y = X + Rs 90

Which gives;

0.8·Y = X - Rs 90 .......................(1)

0.95·Y = X + Rs 90.....................(2)

Subtracting equation (1) from equation (2), we have;

0.95·Y-0.8·Y = X + Rs 90 - (X - Rs 90) = X - X + Rs 90 + Rs 90 = Rs 180

0.15·Y = Rs 180

Y = Rs 180/0.15 = Rs 1200

Therefor, the marked price of the article = Rs 1200

From;

0.8·Y = X - Rs 90, we have;

0.8×Rs 1200 = X - Rs 90

X = 0.8× 1200 + 90 = Rs 1050

Therefore, the cost price of the article = Rs 1050.

6 0
3 years ago
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