Answer:
dude your math period is way too long
Answer:
b. a dilation by a scale factor of 2
Step-by-step explanation:
Which transformation, when performed on the triangle ABC, will result in the transformed figure
A'B'C' being similar but NOT congruent to the original triangle?
a. a reflection over the x-axis
b. a dilation by a scale factor of 2
C.a translation two units to the right
d. a rotation 90° clockwise about the origin
Solution:
Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, translation, reflection and dilation.
Rigid transformation are transformation that preserves the size and shape of a figure. Examples of rigid transformation are reflection, translation and rotation.
Dilation preserves the shape but not the size of a figure.
If translation, rotation or reflection is done on triangle ABC, the transformed figure would be congruent to the original triangle. But, if dilation is done, the transformed figure would be similar but NOT congruent to the original triangle.
Answer is 553 beasts
Step by step:
Multiply 158 by 3 to get 474
Divide 158 by 2 to get 79
Add 474 with 79 and get 553
The final expression in standard form will be 1.601 * 10^9
<h3>Indices and expoenets</h3>
Given the expression as shown:
800.5 * (2*10^6)
This can be further simplified as:

The final expression in standard form will be 1.601 * 10^9
Learn more on indices here: brainly.com/question/10339517
301
We could start by finding the lowest common multiple of 2, 3, 4, 5, and 6, which is 60. Then, we can consider the next few multiples: 120, 180, 240, 300...
However, because we need a remainder of 1 when our number is divided by each of these numbers (2,3,4,5,6), we want to go one above each of these multiples. So we're talking about 61, 121, 181, 241, 301... Those are the numbers that will satisfy the "remainder of 1" part of the question.
Now, we need to find out which one satisfies the other part of the question, which just requires dividing each of these numbers by 7 to see which is divisible by 7 (in other words, which one gives us a remainder of zero when we divide by 7).
301 does it. 301/7 = 43. So 301 is a multiple of 7 and therefore will yield no remainder when divided by 7.
Hope this all makes sense.