All categories

3 years ago

A car went 60 km in 5/6 of an hour while a second car went 54 km in 2/3 h. Which car was faster? How many times faster?

2 answers:

7 0

This is the relationship between distance, velocity and time
v = d/t

To find which car was faster, we need to find the velocity
First car
d = 60 km
t = 5/6 of an hour

Calculate the velocity of the first car
v = d/t
v = 60 ÷ 5/6
v = 60 × 6/5
v = 72
The velocity of the first car is 72 km/hour

Second car
d = 54 km
t = 2/3 of an hour

Calculate the velocity of the second car
v = d/t
v = 54 ÷ 2/3
v = 54 × 3/2
v = 81
The velocity of the second car is 81 km/hour

81 is bigger than 72. The second car was more faster

81 - 72 = 9 km/hour
The second car was 9 km/hour faster than the first car

Margarita [4]3 years ago

3 0

This is the relationship between distance, velocity and timev = d/t
To find which car was faster, we need to find the velocityFirst card = 60 kmt = 5/6 of an hour
Calculate the velocity of the first carv = d/tv = 60 ÷ 5/6v = 60 × 6/5v = 72The velocity of the first car is 72 km/hour
Second card = 54 kmt = 2/3 of an hour
Calculate the velocity of the second carv = d/tv = 54 ÷ 2/3v = 54 × 3/2v = 81The velocity of the second car is 81 km/hour
81 is bigger than 72. The second car was more faster
81 - 72 = 9 km/hourThe second car was 9 km/hour faster than the first car
Read more on Brainly - brainly.com/sf/question/8668399

You might be interested in

In the image below, a = 8 cm and b = 9 cm.

Xelga [282]

Answer:

225 square cm

Step-by-step explanation:

6 0

4 years ago

Read 2 more answers

A stone is thrown vertically upward from a platform that is 20 feet height at a rate of 160 ft/sec. Use the quadratic function h

Nutka1998 [239]

Check the picture below.

$\textit{vertex of a vertical parabola, using coefficients} \\\\ y=\stackrel{\stackrel{a}{\downarrow }}{-16}x^2\stackrel{\stackrel{b}{\downarrow }}{+160}x\stackrel{\stackrel{c}{\downarrow }}{+20} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right)$

$\left(-\cfrac{ 160}{2(-16)}~~~~ ,~~~~ 20-\cfrac{ (160)^2}{4(-16)}\right) \implies \left( - \cfrac{ 160 }{ -32 }~~,~~20 - \cfrac{ 25600 }{ -64 } \right) \\\\\\ \left( 5 ~~~~ ,~~~~ 20 +400 \right)\implies (\stackrel{seconds}{5}~~,~~\stackrel{feet}{420})$

6 0

2 years ago

If anyone Answer this question with POLITICALLY CORRECT answer I'll give you 25+ Points

Tresset [83]

Answer:

$\sqrt[4]{x^5}$

Step-by-step explanation:

A fraction exponent converts into a radical. The denominator is the index of the radical (farthest left number) and the numerator is the exponent of the base inside (the farthest right number). The base of the fraction exponent is the base number in green. To write this expression, simply the exponents into one exponent and one base.

$x^{\frac{3}{4}}x^{\frac{1}{2} } =x^{\frac{3}{4}}x^{\frac{2}{4} } =x^{\frac{3+2}{4}} =x^{\frac{5}{4}}$

Now convert to the radical.

$x^{\frac{5}{4}} = \sqrt[4]{x^5}$

8 0

3 years ago

Don’t understand how to do it

jok3333 [9.3K]

Answer: I think you multiply the fraction together

Step-by-step explanation:

4 0

4 years ago

Read 2 more answers

Rewrite 2x^6-9x^5+4x^2-5/x^3-5 in the form q(x)+r(x)/b(x) what is q(x)?

WITCHER [35]

Hello,

(2x^6-9x^5+4x^2-5)|x^3-5
-(2x^6-10x^3 ) | 2x^3 -9x^2 +10
-------------------
-9x^5 +10x^3 +4x^2-5
-(-9x^5+45x^2)
---------------------------
10x^3-41x^2-5
-(10x^3-50)
-----------------
-41x²+45

Answer D

7 0

3 years ago