AC = 9 m; BC = 16.16 m; BD = 28.27 m; CD = 12.12 m
<em>Find AC
</em>
AC = AB = 9 m
<em>Find BC</em>
∠BAC = 2π – 10π/7 = (14π – 10π)/7 = 4π/7
BC = <em>θr</em> = 4π/7 × 9 m = 16.16 m
<em>Find BD
</em>
∠BAD = π
BD = <em>θr</em> = π × 9 m = 28.27 m
<em>Find CD</em>
<em>C</em> = 2π<em>r
</em>
CD = <em>C</em> – BC – BD = 2π<em>r</em> – 4π<em>r</em>/7 – π<em>r</em> = (14π<em>r</em> – 4π<em>r</em> – 7π<em>r</em>)/7 = (3π/7)<em>r</em>
= (3π/7) ×9 m = 12.12 m
Step-by-step explanation:
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![\text{To draw a graph we need only two points.}\\\text{We choose any value of x, put it to the equation of the line}\\\text{and calculate the value of y:}\\\\for\ x=0\\\\y=\dfrac{4}{3}(0)-5=0-5=-5\to(0,\ -5)\\\\for\ x=3\\\\y=\dfrac{4}{3}(3)-5=4-5=-1\to(3,\ -1)\\\\\text{The graph is in attachment}.](https://tex.z-dn.net/?f=%5Ctext%7BTo%20draw%20a%20graph%20we%20need%20only%20two%20points.%7D%5C%5C%5Ctext%7BWe%20choose%20any%20value%20of%20x%2C%20put%20it%20to%20the%20equation%20of%20the%20line%7D%5C%5C%5Ctext%7Band%20calculate%20the%20value%20of%20y%3A%7D%5C%5C%5C%5Cfor%5C%20x%3D0%5C%5C%5C%5Cy%3D%5Cdfrac%7B4%7D%7B3%7D%280%29-5%3D0-5%3D-5%5Cto%280%2C%5C%20-5%29%5C%5C%5C%5Cfor%5C%20x%3D3%5C%5C%5C%5Cy%3D%5Cdfrac%7B4%7D%7B3%7D%283%29-5%3D4-5%3D-1%5Cto%283%2C%5C%20-1%29%5C%5C%5C%5C%5Ctext%7BThe%20graph%20is%20in%20attachment%7D.)
4.4 miles is the correct answer