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Vesnalui [34]
3 years ago
5

An equation _has one solution. O always sometimes O never

Mathematics
2 answers:
masha68 [24]3 years ago
6 0
Sometimes...............
uysha [10]3 years ago
4 0
An equation sometimes has one solution
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Given the following absolute value function sketch the graph of the function and find the domain and range.
Alja [10]

Step-by-step explanation:

The given absolute value expression is

f(x) =  |x + 3| - 1

This absolute value function is of the form

f(x) =  |x + h|  + k

where (h,k)=(-3,-1) is the vertex.

This function opens upwards, hence the the minimum point is (-3,-1)

The domain is the values of x for which the function is defined.

The domain is all real numbers.

The range is the values of y for which x is defined.

The is y≥-1 because the minimum value is -1.

The graph is shown in attachment.

3 0
3 years ago
What is the slope intercept form equation of the line that passes through (1,3) and (3,7)
Dvinal [7]
I hope this helps you



m = 7-3/3-1


m =2


y -3= 2.(x - 2)


y = 2x+1


2x-y+1=0
5 0
4 years ago
What is the value of X???
nexus9112 [7]

Answer:

5

Step-by-step explanation:

3 0
3 years ago
You go to your favorite store and buy 3 hats h and 2 scarves s you spent $36 total
amid [387]

Answer:

whats the question...........

6 0
3 years ago
Read 2 more answers
V3
valentinak56 [21]

Question:

The angle \theta_1 is located in Quadrant III, and sin(\theta_1) = - \sqrt{\frac{3}{2}}.

What is the value of cos(\theta_1) ?

Express your answer exactly. cos(\theta1) = ________

Answer:

cos(\theta_1) = - \frac{1}{2}

Step-by-step explanation:

Given:

sin(\theta_1) = - \sqrt{\frac{3}{2}}

Since the angle \theta_1 is located in Quadrant III, we have:

sin(\theta_1) = sin(\pi + \frac{\pi}{3})

\theta_1 = \pi + \frac{\pi}{3}

\theta_1 = \frac{4 \pi}{3}

Thus, cos(\theta_1) =

cos(\theta_1) = cos(\pi + \frac{\pi}{3})

cos(\theta_1) = -cos(\frac{\pi}{3})

cos(\theta_1) = - \frac{1}{2}

3 0
4 years ago
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