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3 years ago

Can anyone help me figure out the answer to this

Mathematics

1 answer:

Alex17521 [72]3 years ago

4 0

3x-11=17-4x add 4x to both sides

7x-11=17 add 11 to both sides

7x=28 divide both sides by 7

x=4

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Aurora is planning to participate in an event at her school's field day that requires her to complete tasks at various stations

labwork [276]

Step-by-step explanation:

A. this is a geometric sequence.

according to y-coordinates =>

3, 6, 12, 24

have a T1 = 3 and ratio = 6/3 = 2

B. the formula = Tn = r. T(n-1)

T5 = 2. T4

= 2. 24 = 48 minutes

C. the formula : Tn = T1 . r^(n-1)

T9 = 3. 2^(9-1)

= 3. 2^8

= 3. 256

= 768 munutes

6 0

2 years ago

Imagine that you need to compute e^0.4 but you have no calculator or other aid to enable you to compute it exactly, only paper a

labwork [276]

Answer:

0.0032

Step-by-step explanation:

We need to compute $e^{0.4}$ by the help of third-degree Taylor polynomial that is expanded around at x = 0.

Given :

$e^{0.4}$ < e < 3

Therefore, the Taylor's Error Bound formula is given by :

$|\text{Error}| \leq \frac{M}{(N+1)!} |x-a|^{N+1}$ , where $M=|F^{N+1}(x)|$

$\leq \frac{3}{(3+1)!} |-0.4|^4$

$\leq \frac{3}{24} \times (0.4)^4$

$\leq 0.0032$

Therefore, |Error| ≤ 0.0032

4 0

3 years ago

ASAP WHO EVER ANSWERS THIS WILL BE MARKED BRANLIEST

inn [45]

Answer:

Group 2

Step-by-step explanation:

Because in group 2 they have more 46 year old tourists so it is most likely that the random 46 year old belongs to group 2.

6 0

2 years ago

What of the following are parts of a sphere ?

Tamiku [17]

I believe it’s just the base, radius, and maybe the total surface

7 0

3 years ago

The radius r of a sphere is increasing at a constant rate of 0.04 centimeters per second. (Note: The volume of a sphere with rad

-Dominant- [34]

Answer:

The rate of the volume increase will be $\frac{dV}{dt}=50.27 cm^{3}/s$

Step-by-step explanation:

Let's take the derivative with respect to time on each side of the volume equation.

$\frac{dV}{dt}=4\pi R^{2}\frac{dR}{dt}$

Now, we just need to put all the values on the rate equation.

We know that:

dR/dt is 0.04 cm/s

And we need to know what is dV/dt when R = 10 cm.

Therefore using the equation of the volume rate:

$\frac{dV}{dt}=4\pi 10^{2}0.04$

$\frac{dV}{dt}=50.27 cm^{3}/s$

I hope it helps you!

3 0

2 years ago