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alekssr [168]
3 years ago
8

Can anyone help me figure out the answer to this

Mathematics
1 answer:
Alex17521 [72]3 years ago
4 0
3x-11=17-4x  add 4x to both sides

7x-11=17  add 11 to both sides

7x=28  divide both sides by 7

x=4


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The month of April has 30 days. Corey's iguana eats 2 1/2 ounces of peas a day. How many ounces of peas will Corey's iguana eat
photoshop1234 [79]
It is basically 30 times 2 1/2 which equals 75 ounces. So the iguana will eat 75 ounces in the month of April.
3 0
3 years ago
How do you do this? <br> Find M
Luden [163]

Answer:

Step-by-step explanation:

Let angle ABZ be angle 1 and angle ZBC be angle 2.

Angle 1 = 85 degree

Angle 2 = 6x + 9

measure of angle ABC = 24x+4

Angle 2 = ABC - 85

6x + 9 = 24x + 4 - 85

6x - 24x = 4 - 85 - 9

-18x = -90

x = -90/-18 = 90/18 =

x = 5

Therefore the measure of angle 2 = 6*5 + 9 = 30+9 = 39 degree

Therefore the measure of angle ZBC = 39 degree

Hope you understand

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3 0
3 years ago
What is f(5) for the function f(x)=2x+7
denis-greek [22]

Answer:

Solution:

f(5)=2×5+7

=10+7

=17

8 0
3 years ago
Read 2 more answers
The diameter of a circle is 10 in. Find its area in terms of pie.
kumpel [21]

Answer:

The diameter of the circle = 10 cm

The radius of the circle= 10/2= 5 cm

Step-by-step explanation:

Area of the circle = pi r^2

= pi 5^2

=3.14 *25

= 78.5 cm ^2

7 0
2 years ago
LOTS OF POINTS GIVING BRAINLIEST I NEED HELP PLEASEE
Sidana [21]

Answer:

Segment EF: y = -x + 8

Segment BC: y = -x + 2

Step-by-step explanation:

Given the two similar right triangles, ΔABC and ΔDEF, for which we must determine the slope-intercept form of the side of ΔDEF that is parallel to segment BC.

Upon observing the given diagram, we can infer the following corresponding sides:

\displaystyle\mathsf{\overline{BC}\:\: and\:\:\overline{EF}}

\displaystyle\mathsf{\overline{BA}\:\: and\:\:\overline{ED}}

\displaystyle\mathsf{\overline{AC}\:\: and\:\:\overline{DF}}

We must determine the slope of segment BC from ΔABC, which corresponds to segment EF from ΔDEF.

<h2>Slope of Segment BC:</h2>

In order to solve for the slope of segment BC, we can use the following slope formula:

\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}}  }

Use the following coordinates from the given diagram:

Point B:  (x₁, y₁) =  (-2, 4)

Point C:  (x₂, y₂) = ( 1,  1 )

Substitute these values into the slope formula:

\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}}\:=\:\frac{1\:-\:4}{1\:-\:(-2)}\:=\:\frac{-3}{1\:+\:2}\:=\:\frac{-3}{3}\:=\:-1}

<h2>Slope of Segment EF:</h2>

Similar to how we determined the slope of segment BC, we will use the coordinates of points E and F from ΔDEF to find its slope:

Point E:  (x₁, y₁) =  (4, 4)

Point F:  (x₂, y₂) = (6, 2)

Substitute these values into the slope formula:

\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}}\:=\:\frac{2\:-\:4}{6\:-\:4}\:=\:\frac{-2}{2}\:=\:-1}

Our calculations show that segment BC and EF have the same slope of -1.  In geometry, we know that two nonvertical lines are <u>parallel</u> if and only if they have the same slope.  

Since segments BC and EF have the same slope, then it means that  \displaystyle\mathsf{\overline{BC}\:\: | |\:\:\overline{EF}}.

<h2>Slope-intercept form:</h2><h3><u>Segment BC:</u></h3>

The <u>y-intercept</u> is the point on the graph where it crosses the y-axis. Thus, it is the value of "y" when x = 0.

Using the slope of segment BC, m = -1, and the coordinates of point C, (1,  1), substitute these values into the <u>slope-intercept form</u> (y = mx + b) to solve for the y-intercept, <em>b. </em>

y = mx + b

1 = -1( 1 ) + b

1 = -1 + b

Add 1 to both sides to isolate b:

1 + 1 = -1 + 1 + b

2 = b

Hence, the <u><em>y-intercept</em></u> of segment BC is: <em>b</em> = 2.

Therefore, the linear equation in <u>slope-intercept form of segment BC</u> is:

⇒  y = -x + 2.

<h3><u /></h3><h3><u>Segment EF:</u></h3>

Using the slope of segment EF, <em>m</em> = -1, and the coordinates of point E, (4, 4), substitute these values into the <u>slope-intercept form</u> to solve for the y-intercept, <em>b. </em>

y = mx + b

4 = -1( 4 ) + b

4 = -4 + b

Add 4 to both sides to isolate b:

4 + 4 = -4 + 4 + b

8 = b

Hence, the <u><em>y-intercept</em></u> of segment BC is: <em>b</em> = 8.

Therefore, the linear equation in <u>slope-intercept form of segment EF</u> is:

⇒  y = -x + 8.

8 0
2 years ago
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