1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
WITCHER [35]
3 years ago
10

An instructor wants to write a test with 25 questions where each question is worth 3, 4, or 5 points based on difficulty. He wan

ts the number of 3-point questions to be 4 less than the number of 4-point questions, and he wants the quiz to be worth a total of 100 points. How many 3, 4, and 5 point questions could there be?
Mathematics
1 answer:
irakobra [83]3 years ago
3 0

ANSWER

Find out the how many 3, 4, and 5 point questions could there be.

To proof

Let us assume that the 3 points based question be = x

Let us assume that the 4 points based question be = y

Let us assume that the 5 points based question be = z

As given

An instructor wants to write a test with 25 questions

than the equation become in the form

x + y + z = 25

he quiz to be worth a total of 100 points.

than the equation is becomes

3x + 4y + 5z =100

As given

He wants the number of 3-point questions to be 4 less than the number of 4-point questions

x = y -4

Than the three equation are

x + y + z = 25 ,3x + 4y + 5z =100 and x = y -4

put  x = y -4 in the x + y + z = 25 ,3x + 4y + 5z =100

than

2y + z = 29, 7y +5z= 112

multiply 2y + z = 29 by 5 and subtracted 7y +5z= 112

10 y -7y + 5y -5y = 145 -112

3y = 33

y = \frac{33}{3}

y =11

put in the  x = y -4

x = 11-4

x= 7

put the value of x ,y in the x + y + z = 25

7 + 11 +z =25

18 +z = 25

z = 25 -18

z=7

therefore

numbers of the 3 point question be = 7

numbers of the 4 point question be = 11

numbers of the 5 point question be = 7

Hence proved



You might be interested in
Fill in the table using the graph.
Makovka662 [10]
Find an x value and f(x) is just it's y value. we can start with x=0

when x=0 y= -3

when x= 2 y= -2

and so on, choose easy to read numbers.

you can finish the rest, let me know if you wanna check your answers or if you are stuck.
8 0
3 years ago
Read 2 more answers
PLEASEEEEE HELPPPP BEST ANSWER WILL GET BRAINLIEST LESTSSS GOOO.
USPshnik [31]

Answer:

24

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Simplify i12. 1 −1 −i i
Likurg_2 [28]

Answer:

1

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What’s the correct answer
labwork [276]

There's a strong negative association between the two variables.


6 0
3 years ago
Read 2 more answers
If k = √31 and m = √26, which graph most closely represent the locations of K and M on a number line? The options are in the pic
Dmitry [639]

Answer:

First option

Step-by-step explanation:

√31 = 5.56....

√26 = 5.09....

So m is less than k but greater than 5.

k is greater than k but less than 6.

So the first option is more logical

8 0
3 years ago
Other questions:
  • Paul needs to buy 5/8 pounds of peanuts. the scale at the store measures parts of a pound in sixteenths. what measures equivalen
    9·2 answers
  • Answer sometimes, always, or never
    11·1 answer
  • If two angles of one triangle are congruent to two angles in another triangle, then what must be true of the third angles of the
    6·1 answer
  • Solve each equation for the specified variable y+v=w solve for v
    10·2 answers
  • For algebraic expression 2x4
    9·1 answer
  • To the nearest tenth of a second, how long will it take the arrow to hit the ground?
    10·1 answer
  • Meg surveyed some students at her school about their favorite professional sports. Of the students surveyed, 2 said football was
    8·2 answers
  • PLEASE HELP!!! 30 POINTS AND I NEED IT URGENTLY! FAKE ANSWERS REPORTED
    15·1 answer
  • Use a property of equality to solve this equation:<br><br> 4.5x = 18<br><br> x =
    12·2 answers
  • 3* what =1 because I'm genuinely unsure
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!