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NISA [10]
3 years ago
8

A student estimated the sum 7.95 + 8.11 + 78.5 + 8.05 + 79.4 + 0.815 as: All the numbers begin with a 7 or 8, so use cluster est

imation. 8 + 8 + 80 + 8 + 80 + 0.8 = 184.8 Explain why this reasoning is not accurate.
Mathematics
2 answers:
Alenkinab [10]3 years ago
5 0

Answer with explanation:

We have to estimate the sum of

→7.95 + 8.11 + 78.5 + 8.05 + 79.4 + 0.815

When Rounded to nearest tens

7.95 → 8.00

8.11→ 8.00

78.5→79

8.05→8.00

79.4→79.0

0.815→1

So,estimation of the above rational numbers with addition as an operation is done,the result is

→8 + 8 + 80 + 8 + 80 + 0.8 = 184.8, is not correct ,because in the expression it is not clear , the numbers are neither exactly rounded to nearest tens or tenths.

for example ,79.4 when rounded to nearest tens → 79,but in the expression 80 is written,which is not correct.

Similarly,when rounded to nearest tens, 0.815 → 1, but in the expression 0.8 is written,which is confusing.

Similarly,when rounded to nearest tens ,78.5 →79 , but in the expression 80, is written,which is incorrect.

CaHeK987 [17]3 years ago
3 0

The numbers are not clustered around a common number. Two of the numbers are very large and one is very small.

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In a recent school poll, the administrators asked if students were satisfied with the school's course offerings. What is the pop
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1. All student who attend the school.

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8 0
3 years ago
The following angles are supplementary to each other.
Elan Coil [88]

The value of x in given angles is 36°

<h3>What are supplementary angles?</h3>

When the sum of two angles is 180°, then they are said to be supplements of each other.

Given are two angles which are supplements of each other,

Then according to definition of supplementary angles,

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4 0
2 years ago
Read 2 more answers
What is the x of 2/3x squared minus 6x plus 15
iogann1982 [59]
(2/3)x^2 -6x + 15 = 0
Using the quadratic formula:
x = [-b +-sq root(b^2 - 4 *a*c)] / 2a
x= [--6 +-sq root(36 -4*(2/3)*15] / 2*(2/3)
x= [6 +-sq root 36 -40] / (4/3)

x1 = 4.5 + (2i / (4/3))
x1 = 4.5 + 1.5i
x2 = 4.5 - (2i / (4/3))
x2 = 4.5 - 1.5i




4 0
4 years ago
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