Find the rate of change, (y2-y1)/(x2-x1), from the data given...
(2.16-1.26)/(12-7)=0.18
(1.26-0.72)/(7-4)=0.18
Since the rate is constant, this is a linear equation of the form y=mx+b. Furthermore, since 0 pencils cost 0, b=0, so the cost of the pencils is simply the number of pencils times 18 cents...
c(p)=0.18p (cost with respect to pencils is 0.18 times the number of pencils)
The graph does not represent a function
Answer:
57
Step-by-step explanation:
Let c represent the number of children ($1.75 each) and a represent the number of adults ( $2.00 each).
We know that there were 340 people total, so c + a = 340. This implies that a = 340 - c
We also know that $1.75 c + $2.00 a = $609.25
By substituting a with 340 -c we have $1.75 c + $2.00 (340 -c) = $609.25
Use the distributive property to obtain $1.75 c + $680 - $2.00 c = $609.25
Subtract $680 from both sides and combine like terms to get - $0.25 c = -
$70.75
Now, divide both sides by -$0.25 to get c = 283, the number of children.
The number of adults is 340 - c or 340 - 283 = 57
We are given
Andre rode his bike at a constant speed he rode 1 mile in 5 minutes
Firstly, we will find constant speed
In 5 minutes , distance travelled =1 miles
so, we get speed
Let's assume T is time in minutes
D is the distance in miles
we know that
so, we can plug value
and we get
so, we get
...............Answer
Answer:
In 10 seconds, the garden hose will emit 15 quarts of water.
Step-by-step explanation:
The amount of water emitted by the garden hose over time can be expressed as a ratio: 9/6, or 9 quarts of water for every 6 seconds of time. We can then simplify this ratio to 3/2, or 3 quarts of water for every 2 seconds of time. Since the ratio will remain constant, or the same, over time, we can set up an equivalent ratio, or fraction to find the amount of water emitted in 10 seconds: 3/2 = x/10. We look at the denominators and see that 2 x 5 = 10. In order to make the ratios equivalent, we would also multiply the numerator by 5: 3 x 5 = 15, which gives us the amount of water emitted in 10 seconds.
