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3 years ago

What Is 4x+6y=48 and what is the general form and x intercept and y intercept and slope and factored form?

Mathematics

1 answer:

Vladimir [108]3 years ago

4 0

Given equation : 4x+6y=48 .

The general form of the linear equation is ax +by =c.

The given equation is already in general form.

Let us find x-intercept.

Plugging y =0 in given equation.

4x+6(0)=48 .

4x +0 = 48

4x = 48

Dividing both sides by 4, we get

4x/4 = 48/4

x = 12.

<h3>Therefore, x-intercept is (12,0).</h3>

Let us find y-intercept.

Plugging x =0 in given equation.

4(0)+6y=48 .

6y = 48

Dividing both sides by 6, we get

6y/6 = 48/6

y = 8.

<h3>Therefore, y-intercept is (0,8).</h3>

Let us convert given equation in slope-intercept form y=mx+b.

4x+6y=48

Subtracting 4x from both sides, we get

4x-4x+6y=48-4x

6y = -4x+48

Dividing both sides by 6, we get

6y/6 = -4x/6+48/6

y = -2/3 x +8.

<h3>Therefore, slope is -2/3.</h3>

Let us find factored form now.

GCF of the given linear equation is 2.

Factoring out 2 in all term, we get

3(2x+3y=24)

That is factored form.

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3 years ago

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Right triangle ABC is similar to right triangle DEF. If the side lengths for triangle ABC are 15, 20, 25, respectively, which va

solniwko [45]

Answer:

$A = 15$ $B = 20$ $C = 25$

$D = 30$ $E = 40$ $F = 50$

$D = 3$ $E = 4$ $F = 5$

Step-by-step explanation:

Given

Similar Triangles: ABC and DEF

$A = 15$

$B = 20$

$C = 25$

Required

Determine the sides of DEF

No options were given, so I will solve on a general terms.

Since both triangles are similar, then the following relationship exists.

DEF = ABC * n

i.e.

$D = A * n$ $E = B * n$ $F = C * n$

Where

$n = Scale\ Factor$

Assume n = 2.

So, we have:

$D = A * n$

$D =15 *2$

$D = 30$

$E = B * n$

$E = 20 * 2$

$E = 40$

$F = C * n$

$F = 25 * 2$

$F = 50$

Assume $n = \frac{1}{5}.$

So, we have:

$D = A * n$

$D =15 *\frac{1}{5}$

$D = 3$

$E = B * n$

$E = 20 * \frac{1}{5}$

$E = 4$

$F = C * n$

$F = 25 * \frac{1}{5}$

$F = 5$

So, the possible sides are:

$A = 15$ $B = 20$ $C = 25$

$D = 30$ $E = 40$ $F = 50$

$D = 3$ $E = 4$ $F = 5$

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2 years ago

If lim x-> infinity ((x^2)/(x+1)-ax-b)=0 find the value of a and b

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We have

$\dfrac{x^2}{x+1}=\dfrac{(x+1)^2-2(x+1)+1}{x+1}=(x+1)-2+\dfrac1{x+1}=x-1+\dfrac1{x+1}$

$\displaystyle\lim_{x\to\infty}\left(\frac{x^2}{x+1}-ax-b\right)=\lim_{x\to\infty}\left(x-1+\frac1{x+1}-ax-b\right)=0$

The rational term vanishes as <em>x</em> gets arbitrarily large, so we can ignore that term, leaving us with

$\displaystyle\lim_{x\to\infty}\left((1-a)x-(1+b)\right)=0$

and this happens if <em>a</em> = 1 and <em>b</em> = -1.

To confirm, we have

$\displaystyle\lim_{x\to\infty}\left(\frac{x^2}{x+1}-x+1\right)=\lim_{x\to\infty}\frac{x^2-(x-1)(x+1)}{x+1}=\lim_{x\to\infty}\frac1{x+1}=0$

as required.

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