1) The given equation is 3x-3y=15
To solve for y we subtract 3x both sides:
3x-3x-3y=-3x+15
-3y=-3x+15
With y term -3 is multiplied .We perform the opposite operation both sides that is divide by -3 both sides we have:
y=x-5
Option A :y=x-5 is the right answer.
2) |2x-1|=3
We can remove the absolute sign by forming equations taking both the positive and negative signs:
2x-1=3 or 2x-1=-3
Solving the two equations for x:
2x=3+1 or 2x=-3+1
2x=4 ,x=2. 2x=-2 , x=-1 .
Option a)x=2 or x=-1 is the right answer.
3) 2< 3x-1 ≤ 5
Adding 1 to all the sides we have:
3<3x≤ 6
Dividing by 3 :
1<x≤ 2.
14= 4 pi/6 pi = 2/3
15 = 8 pi/10 pi = 4/5
16 = no
Answer:
y = 20/3
Step-by-step explanation:
4y + 2y + 10 = 50
Combine like terms on the left side.
6y + 10 = 50
Subtract 10 from both sides.
6y = 40
Divide both sides by 6.
y = 40/6
Reduce the fraction by dividing the numerator and denominator by 2.
y = 20/3
Answer:
m a t h
Step-by-step explanation:
i am in middle school so i dont know
