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Maksim231197 [3]
3 years ago
12

Find the equation of the line in slope-intercept form (-1,-1) and (1,0)

Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
3 0

Answer:

An equation in slope-intercept form of the line will be

  • y\:=\frac{1}{2}x-\frac{1}{2}

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where m is the slope and b is the y-intercept

Given the points

  • (-1, -1)
  • (1, 0)

Finding the slope between (-1,-1) and (1,0)

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(-1,\:-1\right),\:\left(x_2,\:y_2\right)=\left(1,\:0\right)

m=\frac{0-\left(-1\right)}{1-\left(-1\right)}

m=\frac{1}{2}

substituting m = 1/2 and (-1, -1) in the slope-intercept form of the line equation to determine the y-intercept

y = mx+b

-1=\frac{1}{2}\left(-1\right)+b

-\frac{1}{2}+b=-1

Add 1/2 to both sides

-\frac{1}{2}+b+\frac{1}{2}=-1+\frac{1}{2}

b=-\frac{1}{2}

substituting m = 1/2 and b = -1/2 in the slope-intercept form of the line equation

y = mx+b

y\:=\frac{1}{2}x+\left(-\frac{1}{2}\right)

y\:=\frac{1}{2}x-\frac{1}{2}

Therefore, an equation in slope-intercept form of the line will be

  • y\:=\frac{1}{2}x-\frac{1}{2}
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