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Mathematics

1 answer:

erma4kov [3.2K]3 years ago

4 0

Answer:

63,081,754

Step-by-step explanation:

sixty-three million: 63 (the millions place)

eighty one thousand: 081 (thousands place)

seven hundred fifty-four (hundreds place)

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labwork [276]

Domain is the numbers you can use
range is the result of inputing the domain

an interesting fact is that the inverse of a function switches the domain and range

basically
the domain of f(x) becomes the range of f^-1(x)
the range of f(x) becomes the domain of f^-1(x)
so just find the domain and range of f(x)

$f(x)=3x- \frac{1}{2}$
there are no restrictions
all real numbers can be used
all real numbers can result

so the answer is domain and range for both is all real numbers

D is answer

7 0

3 years ago

Help me pleasee !!!!

Daniel [21]

Answer:

here (edit I made a mistake)

Step-by-step explanation:

9) $y=\frac{3}{5} x +5$

10) y = x - 3

11) $y=-\frac{3}{5} x - 3$

12) $y=\frac{5}{4} x + 2$

these are the slop int forms, my bad...

sorry

3 0

2 years ago

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sdas [7]

30.......ik lol hahshdkslxpazplaz

5 0

4 years ago

Help me please! If you DO decide to help, please explain it to me since I'm extremely confused! THANK YOU!

den301095 [7]

$\bf \cfrac{(-4x^2)(2x^{-2}y)^3}{(16x^5)(4y^3)^2}\implies \cfrac{(-4x^2)(2^3x^{-2\cdot 3}y^3)}{(16x^5)(4^2y^{3\cdot 2})}\implies \cfrac{(-4x^2)(8x^{-6}y^3)}{(16x^5)(16y^6)} \\\\\\ \cfrac{-32x^{2-6}y^3}{256x^5y^6}\implies -\cfrac{x^{-4} y^3}{8x^5y^6}\implies -\cfrac{1}{8x^5x^{4}y^6y^{-3}}\implies -\cfrac{1}{8x^{5+4}y^{6-3}} \\\\\\ -\cfrac{1}{8x^9y^3}$