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aksik [14]
3 years ago
13

Suppose that a process is currently operating at a 3.5-sigma quality level, and it is planned to use improvement projects to mov

e this process to a 6-sigma level? What project improvement rate would be necessary to achieve that new performance in 2 years?
Mathematics
1 answer:
jenyasd209 [6]3 years ago
7 0

Answer:

11,373 PPM

Step-by-step explanation:

The following  formula is used to compute the Proportion of error-free units given the sigma level in Excel.

<em>  The proportion of error-free units = NORMSDIST(Sigma Level - 1.5) </em>

Suppose that a process is currently operating at a 3.5-sigma quality level.

The proportion of error-free units for this process is

                           NORMSDIST(3.5 - 1.5) = 0.977250

Therefore, the rejection rate is equal to

                  1 - 0.977250 = 0.022750

or 22750 PPM.

Now, consider a 6-sigma level process.

The proportion of error-free units equals

                     NORMSDIST(6.0 - 1.5) = 0.9999966

and the rejection rate is

                             1 - 0.9999966 = 3.4 PPM

Hence, reduction is PPM required per year , that is

                              \dfrac{22750 - 3.4}{2} = 11,373 PPM

reduction per year

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Step-by-step explanation:

4 0
3 years ago
Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by
11111nata11111 [884]

Answer:

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is 8.217 cubic inches.

Step-by-step explanation:

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the open rectangular box ?

Solution :

Let the height be 'x'.

The length of the box is '11-2x'.

The breadth of the box is '7-2x'.

The volume of the box is V=l\times b\times h

V=(11-2x)\times (7-2x)\times x

V=4x^3-36x^2+77x

Derivate w.r.t x,

V'(x)=4(3x^2)-2(36x)+77

V'(x)=12x^2-72x+77

The critical point when V'(x)=0

12x^2-72x+77=0

Solve by quadratic formula,

x=\frac{18+\sqrt{93}}{6},\frac{18-\sqrt{93}}{6}

x=4.607,1.392

Derivate again w.r.t x,

V''(x)=24x-72

Now, V''(4.607)=24(4.607)-72=38.568>0 (+ve)

V''(1.392)=24(1.392)-72=-38.592 (-ve)

So, there is maximum at x=1.392.

The length of the box is l=11-2x

l=11-2(1.392)=8.216

The breadth of the box is b=7-2x

b=7-2(1.392)=4.216

The height of the box is h=1.392.

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is V=l\times b\times h

V=8.216\times 4.216\times 1.392

V=48.217\ in.^3

The volume of the box is 8.217 cubic inches.

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3 years ago
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Phantasy [73]
Subtract 250-50 which equals 200 and then multiply it by 3 which is 600
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Quan's last paycheck shows that he eamed $210.00 for 24 hours of work. What is his hourly rate of pay?
Mariana [72]

Answer:

8.57 explanation:

Step-by-step explanation: If Quan gets 210 dollars every 24 hours and you want to find the amount he gets every hour all you have to do is do 210 divided by 24 which you will get 8.75. So every hour he gets $8.75 every hour for his work

7 0
3 years ago
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Answer:

y - 1 = 1( x -11)

Step-by-step explanation:

I hope this helps you out!

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3 years ago
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