Answer:
52 in approx
Step-by-step explanation:
Given data
Length of TV= 42 in
Widht of TV= 31 in
Required
The diagonal of the TV
Applying the Pythagoras theorem
D^2= L^2+W^2
D= √L^2+W^2
D= √42^2+31^2
D=√1764+961
D=√2725
D=52.20 in
Hence the diagonal of the Tv is 52 in approx
Answer:
l=0.1401P\\
w =0.2801P
where P = perimeter
Step-by-step explanation:
Given that a window is in the form of a rectangle surmounted by a semicircle.
Perimeter of window =2l+\pid/2+w

Or 
To allow maximum light we must have maximum area
Area = area of rectangle + area of semi circle where rectangle width = diameter of semi circle


Hence we get maximum area when i derivative is 0
i.e. 

Dimensions can be

The vertex is (8,7)
the minimum value is 7
the vertex form is y=(x-8)^2 +7
the minimum value of y=7
i hope this helps!