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AURORKA [14]
3 years ago
5

Geometry: Similarity, Congruence, Proofs Question: Why are proofs so picky? Why can’t we just measure the two figures to see if

they are congruent?
Mathematics
1 answer:
FrozenT [24]3 years ago
5 0

Answer:

Haha proofs are an interesting thing. Usually, nothing is to scale, which is why you can't measure anything. They are pretty annoying, but it helps to know why certain things are the way that they are and develop justification skills for higher level math.

Sorry to discourage you, but you're going to see "Justify" quite a lot in calculus and beyond which is basically a more informal version of a proof

you can never escape it tbh lol

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Aaa help pls with this question
amm1812
It wont open it up, so no one can really help
7 0
4 years ago
if a city that currently has a population of 1000 triples in size every 8 years, what will the population be in 24 years?
Kipish [7]
Year 1 - 1000
year 8 -  3000
year 16 - 9000
year 24 - 27000
7 0
4 years ago
Steven has 24 t-shirts. One third of the t-shirts are white, one fourth of the t-shirts are blue ; the remainder of the t-shirts
Black_prince [1.1K]
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8 0
3 years ago
1. Boost Mobile is offering a free phone for a $30.00
Nataliya [291]

Answer:

30+0.68*m

Step-by-step explanation:

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4 0
4 years ago
Find all solutions in the interval from [0,2pi)<br> 2cos(3x)= -sqrt{2}
algol [13]

Solutions of 2cos(3x)= -\sqrt{2} in the interval from [0,2pi) is x =\frac{\pi}{12}  and x = \frac{23\pi}{12} .

<u>Step-by-step explanation:</u>

Find all solutions in the interval from [0,2pi)

2cos(3x)= -\sqrt{2}

⇒ 2cos(3x)= -\sqrt{2}

⇒ \frac{2cos(3x)}{2}= \frac{-\sqrt{2}}{2}

⇒ cos3x= \frac{-\sqrt{2}(\sqrt{2})}{2{\sqrt{2}}}

⇒ cos3x= \frac{-2}{2{\sqrt{2}}}

⇒ cos3x= \frac{-1}{{\sqrt{2}}}

⇒ cos^{-1}(cos3x)= cos^{-1}(\frac{-1}{{\sqrt{2}}})

⇒ 3x=\pm \frac{\pi}{4}

⇒ x=\pm \frac{\pi}{12}

Cosine General solution is :

x = \pm cos^{-1}(y)+ 2k\pi

⇒ x = \pm \frac{\pi}{12}+ 2k\pi , k is any integer .

At k=0,

⇒ x =\frac{\pi}{12} ,

At k=1,

⇒ x = - \frac{\pi}{12}+ 2\pi

⇒ x = \frac{23\pi}{12}

Therefore , Solutions of 2cos(3x)= -\sqrt{2} in the interval from [0,2pi) is x =\frac{\pi}{12}  and x = \frac{23\pi}{12} .

5 0
3 years ago
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