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AURORKA [14]
2 years ago
5

Geometry: Similarity, Congruence, Proofs Question: Why are proofs so picky? Why can’t we just measure the two figures to see if

they are congruent?
Mathematics
1 answer:
FrozenT [24]2 years ago
5 0

Answer:

Haha proofs are an interesting thing. Usually, nothing is to scale, which is why you can't measure anything. They are pretty annoying, but it helps to know why certain things are the way that they are and develop justification skills for higher level math.

Sorry to discourage you, but you're going to see "Justify" quite a lot in calculus and beyond which is basically a more informal version of a proof

you can never escape it tbh lol

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In finding the solution of the equation 5 - 3x = 2x + 9, 3x is added to both sides of the equation first. Which of the following
KIM [24]

Answer:

C should be next

Step-by-step explanation:

Ok after you add 3x to both side you should get this:

5=5x+9

It makes since o subtract 9 from both sides at least for me.

Hope this helps :D

5 0
2 years ago
Read 2 more answers
Eh does anyone know this XD
Yuliya22 [10]

Answer:

9/3

Step-by-step explanation:

It's going up by 9 and going right by 3.

Remember it's rise over run.

3 0
3 years ago
Read 2 more answers
What is .5 as a fraction
NNADVOKAT [17]

Answer:

1/2 is 0.5 as a fraction


8 0
2 years ago
Read 2 more answers
Limited time . 10 points
AfilCa [17]

Answer:

Therefore the value of x is

x=1\pm\sqrt{19}i

Step-by-step explanation:

Given:

x^{2}+20=2x which is

x^{2}-2x+20=0

To Find:

x = ? using Quadratic Formula

Solution:

For a Quadratic Equation ax² + bx + c = 0 , Formula Method is given as

x=\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}

On Comparing with above we get

a=1\\b=-2\\c=20

Substituting a , b , c in Formula method we get

x=\dfrac{-(-2)\pm\sqrt{(-2)^{2}-4(1)(20)}}{2\times 1}\\\\x=\dfrac{2\pm\sqrt{-76}}{2}\\\\x=\dfrac{2\pm2\sqrt{19}i}{2}\\Dividing\ by\ 2\ we\ get\\\\x=1 \pm\sqrt{19}i

Therefore the value of x is

x=1\pm\sqrt{19}i

8 0
3 years ago
300 ml of pure alcohol is poured from a bottle containing 2 l of pure alcohol. Then, 300 ml of water is added into the bottle. A
Ede4ka [16]

Answer:

The present percentage of pure alcohol in the solution is 72.25% of pure alcohol

Step-by-step explanation:

The volume of pure alcohol poured from the 2 l bottle of pure alcohol = 300 ml of pure alcohol

The volume of water added into the bottle after pouring out the pure alcohol = 300 ml of water

The volume of diluted alcohol poured out of the bottle = 300 ml of diluted alcohol

The volume of water added into the bottle of diluted alcohol after pouring out the 300 ml of diluted alcohol = 300 ml of water

Step 1

After pouring the 300 ml of pure alcohol and adding 300 ml of water to the bottle, the percentage concentration, C%₁ is given as follows;

C%₁ = (Volume of pure alcohol)/(Total volume of the solution) × 100

The volume of pure alcohol in the bottle = 2 l - 300 ml = 1,700 ml

The total volume of the solution = The volume of pure alcohol in the bottle +  The volume of water added = 1,700 ml + 300 ml = 2,000 ml = 2 l

∴ C%₁ = (1,700 ml)/(2,000 ml) × 100 = 85% percent alcohol

Step 2

After pouring out 300 ml diluted alcohol from the 2,000 ml, 85% alcohol and adding 300 ml of water, we have;

Volume of 85% alcohol = 2,000 ml - 300 ml = 1,700 ml

The volume of pure alcohol in the 1,700 ml, 85% diluted alcohol = 85/100 × 1,700 = 1,445 ml

The total volume of the diluted solution = The volume of the 85% alcohol in the solution + The volume of water added

∴ The total volume of the twice diluted solution = 1,700 ml + 300 ml = 2,000 ml

The present percentage of pure alcohol in the solution, C%₂ = (The volume of pure alcohol in the 1,700 ml, 85% diluted alcohol)/(The total volume of the diluted solution) × 100

∴ C%₂ = (1,445 ml)/(2,000 ml) × 100 = 72.25 %

The present percentage of pure alcohol in the solution, C%₂ = 72.25%

3 0
3 years ago
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