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GarryVolchara [31]
3 years ago
7

Rewrite 6x-3y=9 in slope intercept form.

Mathematics
2 answers:
anzhelika [568]3 years ago
8 0
1) Subtract 6x from both sides. -3y= -9-6x 
<span>2) Divide both sides by -3. y= 3+2x </span>
<span>2) Put it in slope-intercept form: y=mx+b. y= 2x+3 </span>

<span>Final answer: y=2x+3</span>
Volgvan3 years ago
3 0
Y = mx + b   ----   6x - 3y = 9 ------  - 3y  = 9 - 6x ------ -3y/-3 = 9 - 6x /-3  ----------------------y = 2x - 3.

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aleksandr82 [10.1K]

It's unclear whether the ODE is

xy'+y=4xy^2

or

xy+y'=4xy^2

If the first case, then divide through both sides by y^2 to get

xy^{-2}y'+y^{-1}=4x

then substitute z=y^{-1}, so that z'=-y^{-2}y'. Then

-xz'+z=4x\implies-\dfrac1xz'+\dfrac1{x^2}z=\left(-\dfrac1xz\right)'=\dfrac4x

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If the second, then dividing through by y^2 gives

xy^{-1}+y^{-2}y'=4x

The same substitution as before gives

xz-z'=4x\implies e^{-x^2/2}z'-xe^{-x^2/2}z=\left(e^{-x^2/2}z\right)'=-4xe^{-x^2/2}

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E varies directly with The square root of C. If E=40 When C=25 find: E when C = 49 ( Please help ASAP I need to hand this in tom
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Answer:

E = 56

Step-by-step explanation:

Given that E varies directly with \sqrt{C} then the equation relating them is

E = k\sqrt{C} ← k is the constant of variation

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k = \frac{E}{\sqrt{C} } = \frac{40}{\sqrt{25} } = \frac{40}{5} = 8, thus

E = 8\sqrt{C} ← equation of variation

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E = 8 × \sqrt{49} = 8 × 7 = 56

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Answer:

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Step-by-step explanation:

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