38. 6900 grams
39. 19600 grams
40. 27910 grams
41. 32840 grams
42. 610 grams
43. 970 grams
44. 3712 grams
45. 8937 grams
46. 37 grams
47. 69 grams
48. 1510 grams
49. 4700 grams
50. 150 grams
51. 15 grams
52. 15200 grams
53. 460
I'm sorry if these are wrong but I hope this could help.
Answer:
The answer would be 54
Step-by-step explanation:
<u> ∑ k = 1 88 2.5 ( 1.2 ) k</u><u> is this series written in </u><u>sigma notation. </u>
What is the series written in sigma notation?
- A series can be represented in a compact form, called summation or sigma notation.
- The Greek capital letter, ∑ , is used to represent the sum. The series 4+8+12+16+20+24 can be expressed as 6∑n=14n .
- The expression is read as the sum of 4n as n goes from 1 to 6 .
Given:
2.5 + 2.5(1.2) + 2.5(1.2)2 + ⋯ + 2.5(1.2)87
If we look at the power it is always one less the term i.e., for first term the value of k=0.
So, the series in the form of summation can be written as
∑ k = 1 88 2.5 ( 1.2 ) k
Learn more about sigma notation
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Answer:
Next 3 of the sequence are 4, 7, 10
You are adding by 3.
-2 - -5= 3
-2 + 3=1
1+3=4
4+3=7
7+3=10
Answer:
8.20in³
Step-by-step explanation:
Given V = πr²h
r is the radius = 1.5in
h is the height = 6in
thickness of wall of the cylinder dr = 0.04in
top and bottom thickness dh 0.07in+0.07in = 0.14in
To compute the volume, we will find the value of dV
dV = dV/dr • dr + dV/dh • dh
dV/dr = 2πrh
dV/dh = πr²
dV = 2πrh dr + πr² dh
Substituting the values into the formula
dV = 2π(1.5)(6)•(0.04) + π(1.5)²(6) • 0.14
dV = 2π (0.36)+π(1.89)
dV = 0.72π+1.89π
dV = 2.61π
dV = 2.61(3.14)
dV = 8.1954in³
Hence volume, in cubic inches, of metal in the walls and top and bottom of the can is 8.20in³ (to two dp)
