Answer:
a. y = (3/5)× x +1
Step-by-step explanation:
y= mx+c
m = (13-4)/(20-5) = 9/15 = 3/5
c= 1
so, y= mx+c becomes y= (3/5) × x +1
Here we must see in how many different ways we can select 2 students from the 3 clubs, such that the students <em>do not belong to the same club. </em>We will see that there are 110 different ways in which 2 students from different clubs can be selected.
So there are 3 clubs:
- Club A, with 10 students.
- Club B, with 4 students.
- Club C, with 5 students.
The possible combinations of 2 students from different clubs are
- Club A with club B
- Club A with club C
- Club B with club C.
The number of combinations for each of these is given by the product between the number of students in the club, so we get:
- Club A with club B: 10*4 = 40
- Club A with club C: 10*5 = 50
- Club B with club C. 4*5 = 20
For a total of 40 + 50 + 20 = 110 different combinations.
This means that there are 110 different ways in which 2 students from different clubs can be selected.
If you want to learn more about combination and selections, you can read:
brainly.com/question/251701
Answer: 125/242
Step-by-step explanation: Probability is favorable outcomes over all outcome, since there were 250+234 total outcome, and 250 were favorable (girls), then the probability is 250/250+234=250/484=125/242
Make me the brilranest.thankyou.i hope it was helpful
You just have to think what is 40% of 100 which is 40 then multiply 40 2 times to find out the answer four 40% of 200 when you do 40x2 it =80 so the answer is 80
