No need to fear, thehotdogman93 is here!
The first step is to get rid of those very large numbers. It's going to be very difficult to factor unless we can bring those high numbers down. So lets see if we can factor each term.
So after dividing 49 with every single digit. The only number that divides evenly is 7 and one, and 16 isnt divisible evenly by 7 so that didn't work. Looks like we're gonna have to work with these big numbers.
There is something interesting though about these numbers. 16 and 49 are both perfect squares. 16 is the same as 4^2 and 49 is the same as 7^2. So we can factor the whole trinomial as:

If we were to expand this out as:

and multiply it back into the original form. It would match with the expression we started with. The 4's would multiply back into 16x^2 and the 7's would multiply back into 49.
Additionally 4 * -7 is -28, so you can combine two -28x's into the -56x term in the original trinomial.
Thus, the answer is yes you can, and the answer is:

Answer:
A. 
Step-by-step explanation:
The formula for the volume of a cylinder is the formula for the area of the circle, times the height of the cylinder. The formula for the volume of a circle is,

Multiply that by the height to find the formula for the volume of a cylinder,

Where (pi) represents the value (3.1415), (r) represents the radius, and (h) represents the height of the cylinder. Now substitute in the given values, remember, this problem gives the diameter of the cylinder, divide that value by two to find the radius.

Answer:
Step-by-step explanation:
Answer:
Net income considers operating expenses while gross profit does not.
Step-by-step explanation:
hope this help
brainliest plz
If the function is defined for all
, it means that
is a point who doesn't belong to the domain of the function.
Now, since your function is a ratio, you can't have zero denominator. So, if a point nullifies the denominator, it can't belong to the function domain.
In your case, the denominator is
, which is zero when

So, this function can't be evaluated at
, and in other words, the function is defined when
, so that's the value for
.