Answer:
Step-by-step explanation:
Given that,
f(3) = 2
f'(3) = 5.
We want to estimate f(2.85)
The linear approximation of "f" at "a" is one way of writing the equation of the tangent line at "a".
At x = a, y = f(a) and the slope of the tangent line is f'(a).
So, in point slope form, the tangent line has equation
y − f(a) = f'(a)(x − a)
The linearization solves for y by adding f(a) to both sides
f(x) = f(a) + f'(a)(x − a).
Given that,
f(3) = 2,
f'(3) = 5
a = 3, we want to find f(2.85)
x = 2.85
Therefore,
f(x) = f(a) + f'(a)(x − a)
f(2.85) = 2 + 5(2.85 - 3)
f(2.85) = 2 + 5×-0.15
f(2.85) = 2 - 0.75
f(2.85) = 1.25
Answer: Height at which the wire is attached to the pole is 12 feet.
Explanation:
Since we have given that
Length of the wire = 20 feet
Let the height at which wire is attached to the pole be h
and distance along the ground from the bottom of the pole to the end of the wire be x+4
Now, it forms a right angle triangle so, we can apply "Pythagorus theorem".

But height cant be negative so, height will be 12 feet.
Hence, height at which the wire is attached to the pole is 12 feet.
Their answer is correct so you need explanation?
Answer:
x=(1,0)
g=(3,0)
q=(1,-2)
u=(2,-4)
Step-by-step explanation: