X=8<br> find ∛x=??????????????????

Assume y≠60 which expression is equivalent to (7sqrtx2)/(5sqrty3)

Drupady [299]

Answer:

The equivalent will be:

$\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}=\left(\:x^{\frac{2}{7}}\right)\left(y^{-\frac{3}{5}}\right)$

Therefore, option 'a' is true.

Step-by-step explanation:

Given the expression

$\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}$

Let us solve the expression step by step to get the equivalent

$\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}$

as

$\sqrt[7]{x^2}=\left(x^2\right)^{\frac{1}{7}}$ ∵ $\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a}=a^{\frac{1}{n}}$

$\mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0$

$=x^{2\cdot \frac{1}{7}}$

$=x^{\frac{2}{7}}$

also

$\sqrt[5]{y^3}=\left(y^3\right)^{\frac{1}{5}}$ ∵ $\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a}=a^{\frac{1}{n}}$

$\mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0$

$=y^{3\cdot \frac{1}{5}}$

$=y^{\frac{3}{5}}$

so the expression becomes

$\frac{x^{\frac{2}{7}}}{y^{\frac{3}{5}}}$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}$

$=\left(\:x^{\frac{2}{7}}\right)\left(y^{-\frac{3}{5}}\right)$ ∵ $\:\frac{1}{y^{\frac{3}{5}}}=y^{-\frac{3}{5}}$

Thus, the equivalent will be:

$\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}=\left(\:x^{\frac{2}{7}}\right)\left(y^{-\frac{3}{5}}\right)$

Therefore, option 'a' is true.

5 0

3 years ago

I NEED THE ANSWERS QUICK!!! PLEASE TELL ME ILL GIVE BRAINLIEST!!!!!!!!!!!!

Ulleksa [173]

Answer:

(3,-8) (2,-10)

Step-by-step explanation:

Graph and see where the points are, if they are in the solution, they are correct.

Please mark me brainlist and solve the question I just asked.

Have a good day :)

3 0

3 years ago

What are the coordinates of the image of vertex R after a reflection across the y-axis? (–4, 3) (4, –3) (–3, –4) (3, 4)

bogdanovich [222]

(–4, 3) (4, –3) (–3, –4) (3, 4)

this is a rather simple yet complex concept the easiest way to solve these is to do the exact opposite.

so in this instance it is refrcted across the y-axiss so we swap ONLY the x value NOT the Y ie (-4,3) would switch to (4,3)

same thing would apply if it reflected across x-axis ex (-4,-3)

If it reflect across orgin you change both signs. ex (4,-3)

ie.

(–4, 3) (4, –3) (–3, –4) (3, 4)

changes to

(4, 3) (-4, –3) (3, –4) (-3, 4)

hope it helps

6 0

4 years ago

Read 2 more answers

When your high school teacher says “math” what’s your first reaction?

notsponge [240]

Answer:

"I'm not gonna cry because it's too hard I'm not gonna cry because it's too hard I'm not gonna cry because it's too hard I'm not gonna cry because it's too hard I'm not gonna cry because it's too hard.." Thirty minutes in: ಥ_ಥ

5 0

4 years ago

Read 2 more answers

State the missing factors. there may be more than one correct solution

NikAS [45]

5x5=25

25x2=50

486x2=972

46.5x2=93

12x2=24

320x2=640

3 0

3 years ago

X=8 find ∛x=??????????????????