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erastova [34]
3 years ago
14

Solve for x: -6 < x - 1 < 9

Mathematics
1 answer:
Shkiper50 [21]3 years ago
4 0

Answer:

x = (-5,10)

Step-by-step explanation:

You might be interested in
Two percent of all seniors in a class of 50 have scored above 96% on an ext exam, which of the following is the number of senior
dalvyx [7]

Answer:

The number of seniors who scored above 96% is 1.

Step-by-step explanation:

Consider the provided information.

Two percent of all seniors in a class of 50 have scored above 96% on an ext exam.

Now we need to find the number of seniors who scored above 96%

For this we need to find the two percent of 50.

2% of 50 can be calculated as:

\frac{2}{100}\times50

\frac{100}{100}

1

Hence, the number of seniors who scored above 96% is 1.

6 0
3 years ago
Im not sure help!!!!!!!
kiruha [24]
The answer would be B
5 0
3 years ago
Read 2 more answers
3x~6y=~3<br> 2x+4y=30<br> Elimination using multiplication
Nat2105 [25]
\left \{ {{3x-6y=-3\ \ |*2} \atop {2x+4y=30\ \ | *(-3)}} \right. \\\\ \left \{ {{6x-12y=-6} \atop {-6x-12y=-90}} \right. \\+----\\elimination\\\\&#10;0 \neq -69\\\\There\ are\ no\ solutions
7 0
3 years ago
A bag of corn chips weighs 8 ounces. How many bags of chips weigh 12 pounds?
lora16 [44]
Answer: 24


8 oz is half a pound because a pound is 16 oz, so if you count how many halves go into 12 lbs you get 24 bags
6 0
2 years ago
Someone help me
Aneli [31]

Answer:

see the explanation

Step-by-step explanation:

we know that

The circumference of a circle is equal to

C=\pi D

where

D is the diameter

In this problem we have

C=2.88\ in

\pi=3

substitute and solve for D

2.88=(3)D

D=2.88/3

D=0.96\ in

we know that

The length of the row of quarters is equal to multiply the diameter of the quarter by the number of quarters in the row

so

For 4 quarters in the row, the length is equal to --> 0.96(3)=3.84\ in

For 6 quarters in the row, the length is equal to --> 0.96(6)=5.76\ in

For 12 quarters in the row, the length is equal to -> 0.96(12)=11.52\ in

6 0
3 years ago
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