For the first figure it can be seen that the orientation of the pre-image (<span>∆RST) is the same as that of the image (∆R'S'T').
The image is obtained from the pre-image by shifting the pre-image some units down.
Therefore, the </span><span>single transformation that transforms ∆RST to ∆R'S'T' is a translation.
Part B:</span> <span> For the second figure it can be seen that the orientation of the pre-image (<span>∆RST) is the same as that of the image (∆R'S'T').
The image is obtained from the pre-image by shifting the pre-image some units down and some units to the right.
Therefore, the </span><span>single transformation that transforms ∆RST to ∆R'S'T' is a translation.
Part C: </span></span><span> For the third figure it can be seen that the orientation of the pre-image (<span>∆RST) is not the same as that of the image (∆R'S'T').
The image is obtained from the pre-image by rotating the pre-image some 180 degrees.
Therefore, the </span><span>single transformation that transforms ∆RST to ∆R'S'T' is a rotation.
Part D: </span></span><span> For the fourth figure it can be seen that the orientation of the pre-image (<span>∆RST) is not the same as that of the image (∆R'S'T').
The image is obtained from the pre-image by refrecting the pre-image.
Therefore, the </span><span>single transformation that transforms ∆RST to ∆R'S'T' is a reflection.</span></span>
First add the bottom numbers together (9+6+9) which gives you 24. Then multiply both sides by 3/8 (15 x 3/8= 5 <u>5/8</u>) and (24 x 3/8= <u>9</u>) making your answer 5 5/8 x 9