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allsm [11]
4 years ago
9

Select Translation, Reflection, or Rotation to identify the single transformation that transforms ∆RST to ∆R'S'T'.

Mathematics
2 answers:
ladessa [460]4 years ago
6 0

Answer:

answer in the image below

Step-by-step explanation:

done the topic

mr Goodwill [35]4 years ago
3 0
Part A:

For the first figure it can be seen that the orientation of the pre-image (<span>∆RST) is the same as that of the image (∆R'S'T').

The image is obtained from the pre-image by shifting the pre-image some units down.

Therefore, the </span><span>single transformation that transforms ∆RST to ∆R'S'T' is a translation.



Part B:</span>
<span>
For the second figure it can be seen that the orientation of the pre-image (<span>∆RST) is the same as that of the image (∆R'S'T').

The image is obtained from the pre-image by shifting the pre-image some units down and some units to the right.

Therefore, the </span><span>single transformation that transforms ∆RST to ∆R'S'T' is a translation.


Part C:
</span></span><span>
For the third figure it can be seen that the orientation of the pre-image (<span>∆RST) is not the same as that of the image (∆R'S'T').

The image is obtained from the pre-image by rotating the pre-image some 180 degrees.

Therefore, the </span><span>single transformation that transforms ∆RST to ∆R'S'T' is a rotation.



Part D:
</span></span><span>
For the fourth figure it can be seen that the orientation of the pre-image (<span>∆RST) is not the same as that of the image (∆R'S'T').

The image is obtained from the pre-image by refrecting the pre-image.

Therefore, the </span><span>single transformation that transforms ∆RST to ∆R'S'T' is a reflection.</span></span>
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The alternating current (AC) breakdown voltage of an insulating liquid indicates its dielectric strength. The article "Testing P
zysi [14]

Answer:

Step-by-step explanation:

Hello!

Given the variable

X: breakdown voltage of an insulating liquid under certain conditions.

a)

Graphic in attachment.

Box: The median is closer to the third quartile than the first quartile showing skewness to the left.

The black dot in the middle of the box represents the sample mean (X[bar]) as you can see it is also moved to the right side of the distribution, affected by the presence of an outlier.

Whiskers:

The upper whisker is smaller than the lower one and there is a value that can be considered an outlier.

Altogether you can say that the distribution of the data set is skewed to the left.

b)

To estimate the population mean you need the population to be at least normal. The box plot shows that the distribution is not symmetrical but, considering that the sample size is n= 48 you can apply the Central Limit Theorem and approximate the sampling distribution to normal.

X[bar]≈N(μ;σ²)

As the distribution is approximate, using the sample standard deviation (since we don't know the population value) for the distribution standard deviation is also valid ⇒ Z= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } }

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

∑X= 2626 ∑X²= 144950 n= 48

X[bar]= ∑X/n= 2626/48= 54.71

S²= 1/n[∑X²- (∑X)²/n]= 1/47[144950-(2626)²/48]= 27.36

S= 5.23

Z_{1-\alpha /2}= Z_{0.975}= 1.96

54.71 ± 1.96 * \frac{5.23}{\sqrt{48} }

[53.22; 56.18]kV

c)

95% CI

amplitude a=2 kV  i.e. semi amplitude d= 1 kV

The semi amplitude or margin of error for the CI can be calculated as:

d= Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

From this formula you can clear the sample size

\frac{d}{Z_{1-\alpha /2}} = \frac{S}{\sqrt{n} }

(\frac{d}{Z_{1-\alpha /2}} )*\sqrt{n} = S

\sqrt{n} = S* (\frac{Z_{1-\alpha /2}}{d} )

n = (S* (\frac{Z_{1-\alpha /2}}{d} ))^2

n= (5.23*(\frac{1.96}{1} ))^2= 105.08= 106

3 0
3 years ago
I need this for a test
grin007 [14]

Answer:

-2

Step-by-step explanation:

X= -2 I think so also good luck on your test.

3 0
3 years ago
Caleb solved this equation and recorded his work.
Vladimir79 [104]

Answer:

B) In step 2, the like terms were not combined properly on the right side of the equation.

Step-by-step explanation:

idk

4 0
4 years ago
Read 2 more answers
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9966 [12]

x(x-1)(x+1)(x²+1)=0

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If someone could help u would be amazing!!!!!
GaryK [48]
Tasha's mistake is in Step 4
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