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dusya [7]
3 years ago
13

Define the points ​P(negative 4−4​,negative 2−2​) and ​Q(33​,negative 4−4​). Carry out the following calculation. Find two vecto

rs parallel to ModifyingAbove QP with right arrowQP with length 22.
Mathematics
1 answer:
slega [8]3 years ago
8 0

Answer:

The required vectors are u= and v=.

Step-by-step explanation:

Given information: P(-4,-2) and Q(3,-4).

We need to find the two vectors parallel to \overrightarrow {QP} with length 2.

If A(x_1,y_1) and B(x_2,y_2), then

\overrightarrow {AB}=

|\overrightarrow {AB}|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using the above formula we get

vector QP is,

\overrightarrow {QP}==

Magnitude of vertor QP is,

|\overrightarrow {QP}|=\sqrt{(-4-3)^2+(-2-(-4))^2}

|\overrightarrow {QP}|=\sqrt{(-7)^2+(2)^2}

|\overrightarrow {QP}|=\sqrt{49+4}

|\overrightarrow {QP}|=\sqrt{53}

Using vector is

\widehat {QP}=\frac{\overline {QP}}{|\overline {QP}|}

\widehat {QP}=\frac{1}{\sqrt{53}}

w=\widehat {QP}=\frac{1}{\sqrt{53}}

Multiply vector w by 2 to get a parallel vector parallel of QP in same direction.

u=2w=

Multiply vector w by -2 to get a parallel vector parallel of QP in opposite direction.

v=-2w=

Therefore the required vectors are u= and v=.

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Look at the figure, FHJM. find the length of HJ​
Nat2105 [25]

Answer:

HJ=42\ m

Step-by-step explanation:

we know that

In a parallelogram opposite sides are equal and parallel

The figure FHJM is a parallelogram

so

FH=JM=36\ m

HJ=FM=42\ m

therefore

HJ=42\ m

6 0
3 years ago
Prove or disprove (from i=0 to n) sum([2i]^4) <= (4n)^4. If true use induction, else give the smallest value of n that it doe
ddd [48]

Answer:

The statement is true for every n between 0 and 77 and it is false for n\geq 78

Step-by-step explanation:

First, observe that, for n=0 and n=1 the statement is true:

For n=0: \sum^{n}_{i=0} (2i)^4=0 \leq 0=(4n)^4

For n=1: \sum^{n}_{i=0} (2i)^4=16 \leq 256=(4n)^4

From this point we will assume that n\geq 2

As we can see, \sum^{n}_{i=0} (2i)^4=\sum^{n}_{i=0} 16i^4=16\sum^{n}_{i=0} i^4 and (4n)^4=256n^4. Then,

\sum^{n}_{i=0} (2i)^4 \leq(4n)^4 \iff \sum^{n}_{i=0} i^4 \leq 16n^4

Now, we will use the formula for the sum of the first 4th powers:

\sum^{n}_{i=0} i^4=\frac{n^5}{5} +\frac{n^4}{2} +\frac{n^3}{3}-\frac{n}{30}=\frac{6n^5+15n^4+10n^3-n}{30}

Therefore:

\sum^{n}_{i=0} i^4 \leq 16n^4 \iff \frac{6n^5+15n^4+10n^3-n}{30} \leq 16n^4 \\\\ \iff 6n^5+10n^3-n \leq 465n^4 \iff 465n^4-6n^5-10n^3+n\geq 0

and, because n \geq 0,

465n^4-6n^5-10n^3+n\geq 0 \iff n(465n^3-6n^4-10n^2+1)\geq 0 \\\iff 465n^3-6n^4-10n^2+1\geq 0 \iff 465n^3-6n^4-10n^2\geq -1\\\iff n^2(465n-6n^2-10)\geq -1

Observe that, because n \geq 2 and is an integer,

n^2(465n-6n^2-10)\geq -1 \iff 465n-6n^2-10 \geq 0 \iff n(465-6n) \geq 10\\\iff 465-6n \geq 0 \iff n \leq \frac{465}{6}=\frac{155}{2}=77.5

In concusion, the statement is true if and only if n is a non negative integer such that n\leq 77

So, 78 is the smallest value of n that does not satisfy the inequality.

Note: If you compute  (4n)^4- \sum^{n}_{i=0} (2i)^4 for 77 and 78 you will obtain:

(4n)^4- \sum^{n}_{i=0} (2i)^4=53810064

(4n)^4- \sum^{n}_{i=0} (2i)^4=-61754992

7 0
3 years ago
Asher weighs 15 pounds less ouds less than three times the weight of Audrey hiS sister. Asher weighs 27 pounds
Zigmanuir [339]

Answer: whats the question exactly?

Step-by-step explanation:

5 0
4 years ago
Sean and Kyle have 26 dollars between them. If Sean has 8 more dollars than Kyle, how much money does Kyle have, in dollars?
vredina [299]

Answer: 9$

Step-by-step explanation:

kyle has x dollars. Sean has x+8 dollars. They equal 26. 2x+8=26

2x=18

x=9

7 0
3 years ago
Read 2 more answers
Tourists covered 640 km for a 4 hour ride by car and a 7 hour ride by train. What is the speed of the train, if it is 5 km/h gre
gavmur [86]

Answer:

60 km/h

Step-by-step explanation:

Let us use the x to represent the speed of the car since it is the smaller value.

Then, the distance covered by the car is 4x since was going 4 kph.

The distance covered by the train is (x+5) times 7 or 7x+35.

We know that the total distance covered is 640 km.

Using this information, we can set up the equation 4x+7x+35=640.

By subtracting both sides by 35 and combining the x's, we get a new equation of 11x=605.

After this, we divide both sides by 11 and get x=55.

Lastly, we add 5 to 55 since the train is 5 km faster than the car and that x stood for the car.

Train=60 km/h

5 0
3 years ago
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