Vic and Dan are 2, 897m apart.
<h3>How to determine the distance</h3>
It is important to note that the distance between Vic and Dan is the base of CN
Let's say the distance to Dan is x
The distance to Vic is y
Using cosine ratio, we have
cos α = opposite / adjacent
α = 72°
opposite = 553. 3cm
Adjacent = x
cos 72° = 
Cross multiply
× 
= 
m
The distance to Vic is y
Using the cosine ratio, we have
Cross multiply
m
To determine how far apart Vic and Dan, we use = x + y
= 1790. 61 + 1106. 6
= 2, 897. 21m
= 2, 897m
Thus, Vic and Dan are 2, 897m apart.
Learn more about bearing and distance here:
https://brainly.in/question/47782732
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The first part of the answer can be found by finding the GCF between 15 and 25. 15 is divisible by 1, 3, 5, and 15. 25 is divisible by 1, 5, and 25. You can see that their GCF is 5. Next, you need to look at the variables. The first monomial has a, b, and
. The second monomial has
, b, and c. They each have at least one a, one b, and one c, so those will be in the GCF (abc). If you put that together with the 5, you get that the GCF is
5abc.
As we know, sometimes questions such as these that include the powers and patterns can be a little confusing. I'll walk you through the process of finding this answer.
Firstly, we both know that 10 to the power of 2 simply means this :
10 * 10 = 100
Now, considering we already know what 10 to the power of 2 is, it makes the rest of the question a lot easier. All we have to do is divide 35.6 by the numbers we got.
35.6 / (10 * 10) = 0.356
There you have it, the answer is 0.356. If you need further assistance or you don't understand something, don't hesitate to ask me! I'm always open to people commenting on my profile or even sending me a private message. :)
- Sofie
I am in the middle is class.
