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3 years ago

G=b-ca PLEASE HELP ! what is a ??

Mathematics

1 answer:

Nikitich [7]3 years ago

8 0

G=b-ca
Subtract b from both sides
G-b=-ca
Divide by -c
(G-b)/-c=a

I hope this Helps!

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Solve in systems by substitution y=x+2 and 3x+3y=6

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Answer:

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Step-by-step explanation:

Substitute the first equation into the second equation so 3x + 3(x+2) = 6. Simplify this to get x = 0. Plug x = 0 back into the first equation to get y = 2.

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For the matrices below. Find all (real) eigenvalues. A= [7 9] [0 9]

Jet001 [13]

Answer:

The answer is "9 and 7".

Step-by-step explanation:

Given:

$A=\left[\begin{array}{cc}7&9\\0&9\end{array}\right]$

Using formula:

$|A-\lambda \cdot I|= 0\\\\$

$\to |\left[\begin{array}{cc}7&9\\0&9\end{array}\right]-\lambda \left[\begin{array}{cc}1&0\\0&1\end{array}\right] |=0\\\\\\ \to |\left[\begin{array}{cc}7&9\\0&9\end{array}\right]- \left[\begin{array}{cc}\lambda&0\\0&\lambda\end{array}\right] |=0\\\\\\\to|\left[\begin{array}{cc}7-\lambda &9\\0&9-\lambda\end{array}\right]|=0\\\\\\\to|(7-\lambda)(9-\lambda)|=0\\\\\to (7-\lambda)(9-\lambda)=0\\\\\to 7-\lambda=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 9-\lambda=0\\\\$

$\to \lambda=7 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \lambda=9\\\\$

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3 years ago

Sarah has read aloud in class 3 more times than Joel. Sarah has read 9 times. Which equation represents this situation?

Naya [18.7K]

A j + 3 = 9

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4 years ago