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Ludmilka [50]
3 years ago
5

2/5 of what number is 120

Mathematics
2 answers:
GaryK [48]3 years ago
8 0

Answer:

x = 48

Step-by-step explanation:

Divide 2/5 on both sides, the number you have left over is the value of x, it is a 1-step equation.

(2/5)x = 120  

 

x = 48

Mashcka [7]3 years ago
6 0

Answer:

48

Step-by-step explanation:

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A rectangular painting has
Dmitrij [34]

Answer:

42 square inches.

Step-by-step explanation:

The formula for area is <em>Length x Width</em>

7 x 6 = 42

Then add the units to be specific, and you get:

42 square inches

3 0
3 years ago
W -3/4= -1/8 simplify the awnser as much as possible
oksian1 [2.3K]
The answer to your question is:
<span> w = 5/8 = 0.625</span>
4 0
3 years ago
Find the volume of the composite figure below
Marina86 [1]

Answer:

1386 in³

Step-by-step explanation:

Volume of the composite cone = volume of a hemisphere + volume of a cone

=>Find the volume of cone

Volume of cone = ⅓πr²h

π = 3.142

r = 7 in

h = =√(15² - 7²) [using Pythagorean theorem to solve for height given the slant height and radius]

h = √(225 - 49)

h = √176 ≈ 13 in

Volume of cone = ⅓*3.142*7²*13

= ⅓*2001.454 ≈ 667 in³

=>Find volume of hemisphere.

Volume of hemisphere = ½*volume of sphere = ½*4/3πr³ = ⅔πr³

π = 3.142

r = 7 in

Volume = ⅔*3.142*7³ ≈ 719 in³

<em>Volume of composite figure = 667+719 = 1386 in³</em>

6 0
3 years ago
Consider the original triangle and the reduction.
bulgar [2K]
<h3>answer</h3>

6 cm.

Explanation:

Since they've given use the area of the triangle, we can use the area formula to find the base of the triangle.

The formula to find the area of a triangle is:

a

=

1

2

h

b

→

(

h = height

,

b= base

)

We know:

a

=

24

h

=

8

So we can substitute them in and find

b

:

24

=

1

2

(

8

)

b

Multiply by sides by 2 and then divide:

24

×

2

=

1

2

(

8

)

b

×

2

48

=

8

b

6

=

b

The base of the triangle is

6 cm.

ur welcome ♥️♥️

3 0
3 years ago
The harmonic motion of a particle is given by f(t) = 2 cos(3t) + 3 sin(2t), 0 ≤ t ≤ 8. (a) When is the position function decreas
iren [92.7K]

For the last part, you have to find where f'(t) attains its maximum over 0\le t\le8. We have

f'(t)=-6\sin3t+6\cos2t

so that

f''(t)=-18\cos3t-12\sin2t

with critical points at t such that

-18\cos3t-12\sin2t=0

3\cos3t+2\sin2t=0

3(\cos^3t-3\cos t\sin^2t)+4\sin t\cos t=0

\cos t(3\cos^2t-9\sin^2t+4\sin t)=0

\cos t(12\sin^2t-4\sin t-3)=0

So either

\cos t=0\implies t=\dfrac{(2n+1)\pi}2

or

12\sin^2t-4\sin t-3=0\implies\sin t=\dfrac{1\pm\sqrt{10}}6\implies t=\sin^{-1}\dfrac{1\pm\sqrt{10}}6+2n\pi

where n is any integer. We get 8 solutions over the given interval with n=0,1,2 from the first set of solutions, n=0,1 from the set of solutions where \sin t=\dfrac{1+\sqrt{10}}6, and n=1 from the set of solutions where \sin t=\dfrac{1-\sqrt{10}}6. They are approximately

\dfrac\pi2\approx2

\dfrac{3\pi}2\approx5

\dfrac{5\pi}2\approx8

\sin^{-1}\dfrac{1+\sqrt{10}}6\approx1

2\pi+\sin^{-1}\dfrac{1+\sqrt{10}}6\approx7

2\pi+\sin^{-1}\dfrac{1-\sqrt{10}}6\approx6

4 0
3 years ago
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