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Ludmilka [50]
3 years ago
5

2/5 of what number is 120

Mathematics
2 answers:
GaryK [48]3 years ago
8 0

Answer:

x = 48

Step-by-step explanation:

Divide 2/5 on both sides, the number you have left over is the value of x, it is a 1-step equation.

(2/5)x = 120  

 

x = 48

Mashcka [7]3 years ago
6 0

Answer:

48

Step-by-step explanation:

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What is the basis of statistical inference
Sphinxa [80]

Answer:

Statistical inference is the process of using data analysis to deduce properties of an underlying probability distribution. Inferential statistical analysis infers properties of a population, for example by testing hypotheses and deriving estimates.

3 0
3 years ago
1- find the first term= ?, 90, 540, 3240
Luda [366]

Answer:

1. 15

2. 8

Step-by-step explanation:

The two sequence are geometric progression GP, because they follow a constant multiple (common ratio)

The nth term of a GP is;

Tn = ar^(n-1)

Where;

a = first term

r = common ratio

For the first sequence;

The common ratio r is

r = T3/T2 = 540/90 = 6

r = 6

T2 = ar^(2-1) = ar

T2 = 90 = ar

Substituting the values of r;

90 = a × 6

a = 90/6

a = 15

First term = 15

2. The sam method applies here.

Common ratio r = T3/T2 = 128/32 = 4

r = 4

T2 = ar^(2-1) = ar

T2 = 32 = ar

Substituting the values of r;

32 = a × 4

a = 32/4

a = 8

First term = 8

4 0
3 years ago
BANK, BA=7cm,BK=5.6cm,and angle KBA=85 degree​
ioda
What is the question? What do I do with this information
8 0
3 years ago
can someone plz help me on this plz I beg u
STALIN [3.7K]

Answer:

option A is the correct answer

6 0
3 years ago
Read 2 more answers
Match the logarithmic functions with their corresponding x-values
cricket20 [7]
We have the following functions:
 log2x=5
 log10x=3
 log4x=2
 log3x=1
 log5x=4
 Let's rewrite each function to solve for x:
 x=2^5=32
 x=10^3=1000
 x=4^2=16
 x=3^1=3
 x=5^4=625
 Answer:
 Matching each function with the solution we have:
 log2x=5 ----------->32
 log10x=3---------->1000
 log4x=2------------>16 
 log5x=4------------>625
3 0
3 years ago
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