What is and 20 ft circumference of a circle

Hector would also like to see a professional sumo tournament while he is there, which would cost him ¥5,488. if the conversion r

Keith_Richards [23]

Based on the exchange rate and Victor's budget, hector can see the sumo tournament and have about $322 left over.

<h3>How to find cost of Victor's tournament?</h3>

Amount with Victor = $380

Conversion rate of US dollars to Japanese yen = 1 : 94.153

Cost of the trip = ¥5,488

Ratio of dollar to Yuan

1 : 94.153 = x : 5,488

1/94.153 = x / 5,488

cross product

1 × 5,488 = 94.153x

5,488 = 94.153x

x = 5,488 / 94.153

x = 58.2881055303601

Approximately,

x = $58

Amount left with Victor = Total money with Victor - amount spent

= $380 - $58

= $322

Learn more about ratio:

brainly.com/question/2328454

#SPJ4

8 0

2 years ago

Anthony sold 45 tickets to the school play and Katy sold 40 tickets. What is the ratio of the number of tickets Anthony sold to

Sindrei [870]

Answer:

the answer is 40:45

Step-by-step explanation:

i did the test and got it right

3 0

3 years ago

1. Your high school freshman class had a total of $1200 from fund-raisers during the year. To help

zysi [14]

Answer:

a is 67.20 and b is 1267.20

Step-by-step explanation:

first you have to multiply 1200 from 5.6% and you get 67.20 then you have to add 1200 to 67.20 and you get 1267.20

4 0

3 years ago

A researcher posed a null hypothesis that there was no significant difference between boys and girls on a standard memory test.

kompoz [17]

Complete Question

A researcher posed a null hypothesis that there was no significant difference between boys and girls on a standard memory test. He randomly sampled 40 girls and 40 boys in a community and gave them the standard memory test. The mean score for girls was 68 and the standard deviation of mean was 5.0. The mean score for boys was 66 and the standard deviation of mean was 5.0. What is the p-value and your conclusion at alpha 0.05

Answer:

The p-value is $p-value =0.073614$

The conclusion is

There is sufficient evidence to support the claim that there was no significant difference between boys and girls on a standard memory test

Step-by-step explanation:

From the question we are told that

The sample size of boys and girls is $n_1= n_2 = n = 40$

The standard deviation is $s_1= s_2 = s = 5$

The level of significance is $\alpha = 0.05$

The sample mean for boys is $\= x_1 =66$

The null hypothesis is $H_o : \mu_1 = \mu_2$

The alternative hypothesis is $H_a : \mu_1 < \mu_2$

Generally the test statistics is mathematically represented as

$z = \frac{\= x_1 - \= x_2 }{ \sqrt{\frac{s_1 ^2 }{n_1} + \frac{s_2 ^2 }{n_1} } }$

=> $z = \frac{66 -68 }{ \sqrt{\frac{5^2 }{40} + \frac{5 ^2 }{40} } }$

=> $z = -1.789$

From the z table the area under the normal curve to the left corresponding to -1,789 is

$P(Z < -.1789 ) = 0.036807$

Generally the p-value is mathematically represented as

$p-value = 2 P(Z < -.1789 )$

=> $p-value = 2 * 0.036807$

=> $p-value =0.073614$

From the values obtained we see that $p-value < \alpha$ hence

The decision rule is

Fail to reject the null hypothesis

The conclusion is

There is sufficient evidence to support the claim that there was no significant difference between boys and girls on a standard memory test

3 0

3 years ago

A fair coin is tossed .if the coin is tails one die is rolled and the number on the die is recorded if the coin toss is heads tw

svp [43]

So for the dice to be 9 two die must be rolled. So we start with a 1/2 chance.

Then there are 36 possibilities to be rolled on a die (6*6) and there are 4/36 possibilities for the dice to roll a 9 (4+5, 5+4, 3+6, 6+3).

So we multiply 1/2 by 1/9 (4/36)- which equals 1/18.

So there is a 1/18 chance for the result of the dice rolled to be a 9.

I hope this helps!

6 0

3 years ago