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nirvana33 [79]
3 years ago
5

Find the sum of 12th term of the following AP series 7,11 and 15.​

Mathematics
2 answers:
Ahat [919]3 years ago
7 0

Answer:the sum of the 12th term of the AP is 348

Step-by-step explanation:

7,11,15

Common difference=d=11-7

d=4

First term=7

Using the formula

Sn=n/2 x (2a+d x (n-1))

S12=12/2 x (2x7+4x(12-1))

S12=6 x (14+4x11)

S12=6 x (14+44)

S12=6 x 58

S12=348

Alexandra [31]3 years ago
4 0
It is adding 4 each time.

Just calculate the first 12 terms and add them up.

Term 1 = 7 + 4*0 = 7
Term 2 = 7 + 4*1 = 11
Term 3 = 7 + 4*2 = 15
Term 4 = 7 + 4*3 = 19
Term 5 = 7 + 4*4 = 23
Term 6 = 7 + 4*5 = 27
Term 7 = 7 + 4*6 = 31
Term 8 = 7 + 4*7 = 35
Term 9 = 7 + 4*8 = 39
Term 10 = 7 + 4*9 = 43
Term 11 = 7 + 4*10 = 47
Term 12 = 7 + 4*11 = 51

Sum of first 12 terms = 348
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2 planes leave the airport at the same time. their speeds are 140 mph and 170 mph and the angle between their courses is 25 degr
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Answer:

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Step-by-step explanation:

Note that we are considering two planes.

Plane 1

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Plane 2

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The angle between side is 25 degree

From cosine rule

c^2 = a^2 + b^2 − 2abcos(tetha)

Where a = 350

b = 425miles

c^2 = 350^2+425^2-2(350×425)(cos25)

c^2 = 122500+180625-297500(0.906)

c^2 = 303125-269535

c^2 = 33590

C = √33590

C = 183.27miles

The distance they flew apart after 2.5hrs is 183.27miles

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Answer:

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