Question

Cada par de puntos determina una recta con la pendiente dada. Halla el valor de la incógnita en cada caso: a. (3,2);(4,x); m=1 b. (b,-1);(2,-2); m=-1/2 c. (5,d);(9,2); m=-3/4 d. (-1/3,3/4);(h,5/6); m=7/12

Answer 1

Answer:

a=3,b=0,c=5,d=-4/21

Step-by-step explanation:

The formule we use to get the slope is:

m = $\frac{y2-y1}{x2-x1}$

a. (3,2);(4,x); m=1

$\frac{x-2}{4-3}=1$  → x= (1)(4-3)+2 → 3

b. (b,-1);(2,-2); m=-1/2

$\frac{-2-(-1)}{2-b}=\frac{-1}{2}$  → -1= ($\frac{-1}{2}$)(2-b) →  $\frac{-1}{\frac{-1}{2} }-2$ → 0

c. (5,d);(9,2); m=-3/4

$\frac{2-d}{9-5}=\frac{3}{4}$  →  d= ($\frac{-3}{4}$)(9-5)-2 → 5

d. (-1/3,3/4);(h,5/6); m=7/12

$\frac{\frac{5}{6}-\frac{3}{4} }{h-\frac{-1}{3} }=\frac{7}{12}$   →  $\frac{5}{6}-\frac{3}{4}$=  $\frac{7}{12}$ (${h-\frac{-1}{3} }$)  →  $\frac{-4}{21}$

We get this equation with the original one:

y=mx+b

There are three  forms of linear equations:

point-slope form y2-y1=m(x2-x1)

standard form Ax + By + C = 0 or Ax + By = C

and slope-intercept form y=mx+b