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3 years ago

2 ÷ 1

Mathematics

2 answers:

maxonik [38]3 years ago

8 0

Answer:

14/5 or

2.8 or

2 4/5

Step-by-step explanation:

Math

pshichka [43]3 years ago

7 0

Answer:

2.8 or 14/5

keep change change

2×7=14

5×1=5

Step-by-step explanation:

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If the hypotenuse of a right triangle is 30 cm long and one leg is twice as long as the other, how long are the legs of the tria

Talja [164]

30^2=a^2+2(a)^2
900=a^2+4a^2
900=5a^2
180=A^2
6√5=a
a=13.4164cm

8 0

3 years ago

What is the length of the hypotenuse of a right triangle with sides 9yards and 12 yards respectively?

Andrews [41]

Answer:

15 yards

Step-by-step explanation:

use pythagoras theorem

a^2 + b^2 = c^2

9^2 + 12 ^2

81 + 144

225

square root

hypoteneuse= 15 yards

8 0

3 years ago

A woman bought a number of items for $24. She realized that if she had bought 4 more items for

Roman55 [17]

Answer:

The woman bought 2 items at $12 each.

Step-by-step explanation:

Given that a woman bought a number of items for $ 24, and she realized that if she had bought 4 more items for the same money, she would have paid $ 8 less per item, to determine how many Items did she buy the following calculation must be done:

X = 24

X + 4 = 24

24/2 = 12

24/6 = 4

12 - 4 = 8

Therefore, the woman bought 2 items.

3 0

3 years ago

Find an equation of the line that passes through the point and has the indicated slope m. (let x be the independent variable and

zhenek [66]

I think that x is on they y axis and what connects between that is 2,-3

4 0

4 years ago

Lines k and n intersect on the y-axis

avanturin [10]

a) The equation of line k is:

$y = -\frac{202}{167}x + \frac{598}{167}$

b) The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

The equation of a line, in <u>slope-intercept formula</u>, is given by:

$y = mx + b$

In which:

m is the slope, which is the rate of change.
b is the y-intercept, which is the value of y when x = 0.

Item a:

Line k intersects line m with an angle of 109º, thus:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

In which $m_1$ and $m_2$ are the slopes of <u>k and m.</u>

Line k goes through points (-3,-1) and (5,2), thus, it's slope is:

$m_1 = \frac{2 - (-1)}{5 - (-3)} = \frac{3}{8}$

The tangent of 109 degrees is $\tan{109^{\circ}} = -\frac{29}{10}$
Thus, the slope of line m is found solving the following equation:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

$-\frac{29}{10} = \frac{m_2 - \frac{3}{8}}{1 + \frac{3}{8}m_2}$

$m_2 - \frac{3}{8} = -\frac{29}{10} - \frac{87}{80}m_2$

$m_2 + \frac{87}{80}m_2 = -\frac{29}{10} + \frac{3}{8}$

$\frac{167m_2}{80} = \frac{-202}{80}$

$m_2 = -\frac{202}{167}$

Thus:

$y = -\frac{202}{167}x + b$

It goes through point (-2,6), that is, when $x = -2, y = 6$ , and this is used to find b.

$y = -\frac{202}{167}x + b$

$6 = -\frac{202}{167}(-2) + b$

$b = 6 - \frac{404}{167}$

$b = \frac{6(167)-404}{167}$

$b = \frac{598}{167}$

Thus. the equation of line k, in slope-intercept formula, is:

$y = -\frac{202}{167}x + \frac{598}{167}$

Item b:

Lines j and k intersect at an angle of 90º, thus they are perpendicular, which means that the multiplication of their slopes is -1.

Thus, the slope of line j is:

$-\frac{202}{167}m = -1$

$m = \frac{167}{202}$

Then

$y = \frac{167}{202}x + b$

Also goes through point (-2,6), thus:

$6 = \frac{167}{202}(-2) + b$

$b = \frac{(2)167 + 202(6)}{202}$

$b = \frac{1546}{202}$

The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

A similar problem is given at brainly.com/question/16302622

7 0

2 years ago