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3 years ago

A sample of gas (1.3 mol) occupies __________ l at 22 Â°c and 2.5 atm.

1 answer:

4 0

To answer this question, you just need to put all the variable into <span>PV = nRT formula. In this case, the pressure(P) is 2.5 atm, the number of molecule(n) is 1.3 mol, the temperature(T) is 22 celcius= 295.15 kelvin.
Then the volume should be:

</span><span>PV = nRT
</span>2.5 * V = 1.3 * <span>0.08206* 295.15
</span>V= 12.59L

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Which statement explains why a molecule of CH4 is nonpolar?

Lerok [7]

Answer:

The geometric shape of a CH4 molecule distributes the charges symmetrically.

Explanation:

The dipole moment is ruled by the compound's geometry and elements electronegativity difference.

Arranging the forces acording to the elements electronegativity difference withing the molecule geometry will yeld the dipole moment.

If the forces cancel out, it is a nonpolar compound.

If the forces does not cancel out it is a polar compound.

Picture of such analysis for methane is attached.

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4 years ago

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Write the uses of isotopes used for treatment of cancer ?!?!

bazaltina [42]

Answer:

Yttrium-90 is used for treatment of cancer, particularly non-Hodgkin's lymphoma and liver cancer, and it is being used more widely, including for arthritis treatment. Lu-177 and Y-90 are becoming the main RNT agents. Iodine-131, samarium-153, and phosphorus-32 are also used for therapy.

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2 years ago

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a 15.00 mL sample of an unknown HClO4 solution requires titration with 25.64 mL of 0.2000 M NaOH to reach equivalence point. wha

Veronika [31]

Answer:

V₁ = 0.342 M

Explanation:

Given data:

Volume of HClO₄ = 15.00 mL

Volume of NaOH = 25.64 mL

Molarity of NaOH = 0.2000 M

Molarity of HClO₄ = ?

Solution:

Formula:

M₁V₁ = M₂V₂

V₁ = M₂V₂ /M₁

V₁ = 0.2000 M ×25.64 mL /15.00 mL

V₁ = 5.128 M. mL /15.00 mL

V₁ = 0.342 M

5 0

3 years ago

The group of cells that are organized into columns and rows

Brrunno [24]

Explanation:

vertical columns and horizontal rows, hope it helps

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3 years ago

How many atoms are in 1.4 moles of H3PO4?

sdas [7]

<h3>Answer:</h3>

8.4 × 10²³ atoms H₃PO₄

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Moles
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 1.4 moles H₃PO₄

[Solve] atoms H₃PO₄

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

[DA] Set up: $\displaystyle 1.4 \ mol \ H_3PO_4(\frac{6.022 \cdot 10^{23} \ atoms \ H_3PO_4}{1 \ mol \ H_3PO_4})$
[DA] Multiply [Cancel out units]: $\displaystyle 8.4308 \cdot 10^{23} \ atoms \ H_3PO_4$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

8.4308 × 10²³ atoms H₃PO₄ ≈ 8.4 × 10²³ atoms H₃PO₄

3 0

3 years ago