Answer:
A. 4.5 mol Mg(OH)₂
B. 6 mol NaOH
Explanation:
Let's consider the following balanced equation.
Mg(NO₃)₂ + 2 NaOH ⇒ Mg(OH)₂ + 2 NaNO₃
PART A
The molar ratio of NaOH to Mg(OH)₂ is 2:1. The moles of Mg(OH)₂ produced from 9 moles of NaOH are:
9 mol NaOH × 1 mol Mg(OH)₂/2 mol NaOH = 4.5 mol Mg(OH)₂
PART B
The molar ratio of NaOH to NaNO₃ is 2:2. The moles of NaOH needed to produce 6 moles of NaNO₃ are:
6 mol NaNO₃ × 2 mol NaOH/2 mol NaNO₃ = 6 mol NaOH
Answer:
63.36gallons
Explanation:
Given:
Volume of water used for dialysis = 2.4 x 10²L
Solution:
We are to convert from liters to gallons.
The conversion factor is shown below:
1L = 0.264gallons
To convert to litre:
since 1L = 0.264gallons
2.4 x 10²L = (2.4 x 10² x 0.264)gallons; 63.36gallons
Answer:
The specific heat of the alloy 
Explanation:
Mass of an alloy
= 25 gm
Initial temperature
= 100°c = 373 K
Mass of water
= 90 gm
Initial temperature of water
= 25.32 °c = 298.32 K
Final temperature
= 27.18 °c = 300.18 K
From energy balance equation
Heat lost by alloy = Heat gain by water
[
-
] =
(
-
)
25 ×
× ( 373 - 300.18 ) = 90 × 4.2 (300.18 - 298.32)

This is the specific heat of the alloy.
Lysosomes are simlar to vacuoles by them working together basically. they both are enclosed organelle compartments within cell. vacuoles store the food waste, bacteria, etc. while the lysosomes breaks them down
The correct answer is A, since it is the only sensible answer.