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3 years ago

9

Perfect Squaress less than 30

1 answer:

levacccp [35]3 years ago

5 0

The perfect whole squares are 1, 4, 9, 16, 25, 36, 49, 64, 81, 100.

Less than 30 are:

<h2>1, 4, 9, 16, 25</h2>

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Solve x2 – 4x – 9 = 29 for x.

Irina-Kira [14]

$x^2 - 4x - 9 = 29 \\ x^2 - 4x - 9 - 29 = 0 \\ x^2 - 4x - 38 = 0 \\ x= \frac{-b \pm \sqrt{ b^{2} -4ac} }{2a} 
$ ; where a = 1, b = -4 and c = -38
$x= \frac{-(-4) \pm 
\sqrt{ 
(-4)^{2} -4 \times 1 \times -38} }{2 \times 1} \\ = \frac{4 \pm \sqrt{ 16 +152} }{2} \\ =\frac{4 \pm \sqrt{ 168} }{2} \\ =\frac{4 \pm 
2\sqrt{42} }{2} \\ 
=2+\sqrt{42} \ or \ 2-\sqrt{42}\\=8.48 \ or \ -4.48$

8 0

2 years ago

Read 2 more answers

I need help! I'm *so* confused! I will mark Brainliest

Naddik [55]

Answer:

(-2,21)

Step-by-step explanation:

2 days ago, Paulo's commute time was halfway between his commute times 8 and 9 days ago.

8 days ago means that x-coordinate -8 represents this day. Count 8 units to the left and find that when x = -8, y = 24 minutes.

9 days ago means that x-coordinate -9 represents this day. Count 9 units to the left and find that when x = -9, y = 18 minutes.

Find halfway commute time between points (-8,24) and (-9,18):

$y=\dfrac{24+18}{2}=\dfrac{42}{2}=21,$

then coordinates that Paulo should graph are

(-2, 21)

(-2 means 2 days ago, 21 is the halfway)

5 0

2 years ago

A new test to detect TB has been designed. It is estimated that 88% of people taking this test have the disease. The test detect

Elodia [21]

Answer:

Correct option: (a) 0.1452

Step-by-step explanation:

The new test designed for detecting TB is being analysed.

Denote the events as follows:

<em>D</em> = a person has the disease

<em>X</em> = the test is positive.

The information provided is:

$P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99$

Compute the probability that a person does not have the disease as follows:

$P(D^{c})=1-P(D)=1-0.88=0.12$

The probability of a person not having the disease is 0.12.

Compute the probability that a randomly selected person is tested negative but does have the disease as follows:

$P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264$

Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:

$P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188$

Compute the probability that a randomly selected person is tested negative as follows:

$P(X^{c})=P(X^{c}\cap D)+P(X^{c}\cap D^{c})$

$=0.0264+0.1188\\=0.1452$

Thus, the probability of the test indicating that the person does not have the disease is 0.1452.

4 0

2 years ago

The mean of 15 numbers is y.If each of the number is increased by 30, find the increase of the new mean in terms of y.The answer

dusya [7]

Answer:

y+30

Step-by-step explanation:

the sum of the numbers is 15y

the new sum after increase each number by 30 is 15y+450

the new mean 15y+450/15

= y+30

4 0

2 years ago

What is the mixed number for 24/3

galben [10]

The mixed number is 8

8 0

3 years ago

Read 2 more answers