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never [62]
3 years ago
15

Evaluate the limit using the appropriate Limit Law(s). (If an answer does not exist, enter DNE.) lim x→8 1 + 3 x 5 − 6x2 + x3

Mathematics
1 answer:
Sergio [31]3 years ago
5 0

Answer:

[tex] lim_{x \to 8} (1+3\sqrt{x})(1-6x^2 +x^3)=1-384 +512+3\sqrt{8} -18(8)^{5/2} +3 (8)^{7/2} =1223.601

And the limit on this case exists.

Step-by-step explanation:

We want to find the following limit:

lim_{x \to 8} (1+3\sqrt{x})(1-6x^2 +x^3)

First we can distribute the polynomials like this:

lim_{x \to 8} (1-6x^2 +x^3+3\sqrt{x} -18 x^{5/2} +3x^{7/2})

And Now we can use the distributive property for the limit and we got:

lim_{x \to 8} 1 - 6 lim_{x \to 8} x^2 + lim_{x \to 8} x^3 +3 lim_{x \to 8} \sqrt{x} -18 lim_{x \to 8} x^{5/2} + 3 lim_{x \to 8} x^{7/2}

And now we can evaluate the limit and we got:

[tex] lim_{x \to 8} (1+3\sqrt{x})(1-6x^2 +x^3)=1-384 +512+3\sqrt{8} -18(8)^{5/2} +3 (8)^{7/2} =1223.601

And the limit on this case exists.

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eimsori [14]
B.) Hibiscus Street 

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Anuta_ua [19.1K]

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Step-by-step explanation:

Use Distance = Speed*Time to find the two missing values with the data that is provided for those two cases [<em>in brackets</em>].

MPH MILES     HOURS

 50            20      [<em>0.4]</em>

 [<em>40</em>]    <u>70</u>      <u>1.75</u>

Totals   90 miles   2.15 hours

Average = 90 miles/2.15 hours

     41.86 mph

5 0
3 years ago
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