The probability of drawing only one red card in two draws without replacement is given by:
The probability of drawing two red cards in two draws without replacement isgiven by:
The events 'draw one red card' and 'draw two red cards' are mutually exclusive. Therefore the probability of drawing at least one red card is 0.51 + 0.245 = 0.755.
Answer:
2 + 3i, midpoint is (2,3)
Step-by-step explanation:
we need to find the midpoint between (-1+9i) and B=(5-3i)
To find the midpoint of two points (a+bi) and (c+di) in a complex plane,
we apply formula
A = (-1+9i) and B=(5-3i)
Midpoint for AB is
2 + 3i , so midpoint is (2,3)
To solve problem 19, we must remember the order of operations. PEMDAS tells us that we should simplify numbers in parentheses first, exponents next, multiplication and division after that, and finally addition and subtraction. Using this knowledge, we can begin to simplify the problem by working out the innermost set of parentheses:
36 / [10 - (3-1)²]
36 / [10 - (2)²]
Next, we should still simplify what is inside the parentheses but continue to solve the exponents (the next letter in PEMDAS).
36/ (10-4)
After that, we should compute the subtraction that is inside the parentheses.
36/6
Finally, we can solve using division.
6
Now, we can move onto problem 20:
1/4(16d - 24)
To solve this problem, we need to use the distributive property, which allows us to distribute the coefficient of 1/4 through the parentheses by multiplying each term by 1/4.
1/4 (16d-24)
1/4(16d) - 1/4(24)
Next, we can simplify further by using multiplication.
4d - 6
Therefore, your answer to problem 19 is 6 and the answer to problem 20 is 4d -6.
Hope this helps!
