All categories

2 years ago

How do you bisect angles???

Mathematics

1 answer:

Leokris [45]2 years ago

8 0

Answer:

• Using a ruler draw two straight lines to make an angle

• Put the pin of the compass at the point of the angle.

• Set the other end of the compass to a point most of the way up one of the lines and draw an arc across each line.

•Mark the points where the arc crosses each line.

Step-by-step explanation:

I hope it helps

have a nice day

#Captainpower

You might be interested in

determine the length of side y, to the nearest tenth, in each of the following triangles. Please show work

umka21 [38]

The final answer is 10.9

6 0

2 years ago

A model of a house has been drawn on a coordinate grid. One corner of the house has been drawn at (1,5). The drawing will be tra

asambeis [7]

It should me b I don’t know if it is but it should be

7 0

3 years ago

Helppppppppppppppppppp I’ll mark you brainlist don’t respond if you’re going to put something random I will report you :)

Basile [38]

Answer:

35°

Step-by-step explanation:

Angles on a straight line add up to 180, so 180-145 is equal to

3 0

2 years ago

PLEASE HELP WITH QUESTION! MARKING BRAINLIEST + POINTS GIVEN.

I am Lyosha [343]

The simple answer (not using multiples of 2 $\pi$ (360°)) is
$= \sqrt[3]{125} ((cos( \frac{288}{3})) + isin(( \frac{288}{3})))
= 5(cos96 + isin96)$

8 0

2 years ago

You are given the following information obtained from a random sample of 5 observations. 20 18 17 22 18 At 90% confidence, you w

Margaret [11]

Answer:

The null hypothesis is

$H_o : \mu = 21$

The Alternative hypothesis is

$H_a : \mu< 21$

$\sigma_{\= x} = 0.8944$

$t = -2.236$

Yes the mean population is significantly less than 21.

Step-by-step explanation:

From the question we are given

a set of data

20 18 17 22 18

The confidence level is 90%

The sample size is n = 5

Generally the mean of the sample is mathematically evaluated as

$\= x = \frac{20 + 18 + 17 + 22 + 18}{5}$

$\= x = 19$

The standard deviation is evaluated as

$\sigma = \sqrt{ \frac{\sum (x_i - \= x)^2}{n} }$

$\sigma = \sqrt{ \frac{ ( 20- 19 )^2 + ( 18- 19 )^2 +( 17- 19 )^2 +( 22- 19 )^2 +( 18- 19 )^2 }{5} }$

$\sigma = 2$

Now the confidence level is given as 90 % hence the level of significance can be evaluated as

$\alpha = 100 - 90$

$\alpha = 10$ %

$\alpha =0.10$

Now the null hypothesis is

$H_o : \mu = 21$

the Alternative hypothesis is

$H_a : \mu< 21$

The standard error of mean is mathematically evaluated as

$\sigma_{\= x} = \frac{\sigma}{ \sqrt{n} }$

substituting values

$\sigma_{\= x} = \frac{2}{ \sqrt{5 } }$

$\sigma_{\= x} = 0.8944$

The test statistic is evaluated as

$t = \frac{\= x - \mu }{ \frac{\sigma }{\sqrt{n} } }$

substituting values

$t = \frac{ 19 - 21 }{ 0.8944 }$

$t = -2.236$

The critical value of the level of significance is obtained from the critical value table for z values as

$z_{0.10} = 1.28$

Looking at the obtained value we see that $z_{0.10}$ is greater than the test statistics value so the null hypothesis is rejected

6 0

3 years ago