The graph of h(x) = 3x^2 is a curved "bowl" like shape that opens upward. The curve is called a parabola. The two ends go on forever upward. It has symmetry along the y axis.
In contrast, the graph f(x) = x is a straight line that goes through (0,0) and (1,1). This is known as a linear equation.
Answer:
When looking at this model, and asking yourself the question, is PRB congruent to QSB? PRB is in fact congruent to QSB. Congruent means that two figures have the same shape/size, no matter if it's mirrioring or not it is congruent. In this image, PRB is one shape, and QSB is another. They have the exact same points and they're also the same shape, but one is flipped the right side up. It was also stated PQ and RS bisect eachother at point B, <p is congruent to <Q, and <R is congruent to <S proving all these connections make this figure conguent.
Step-by-step explanation:
I'm learning the exact same thing so give me some question and I can see what I can do!
We determine line m as follows:
*First, by theorem we have the following:
Here m1 & m2 are the slopes of two perpendicular lines. For all lines that are perpendicular that is true, so we calculate the slope of line m using the slope of the function given [Which has a slope of 7/4]:
So, the slope of line m is -4/7. Now, using this slope and the point (-1, 4) we replace in the following expression:
Here x1, y1 & m1 are the x-component of the point, the y-component of the point, and the slope of the line respectively, so we replace and solve for y:
And that last function of y is the line m.
Answer:
x^2 + 2xy + y ^2
Step-by-step explanation:
A = a^2
a = x + y
(x + y) + (x + y)
x^2 + xy + xy + y^2
x^2 + 2xy + y ^2
