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saw5 [17]
2 years ago
6

Donald's Donuts makes both chocolate and plain glazed donuts. Each Saturday, they make 13 plain glazed donuts for every 7 chocol

ate glazed donuts. What is the ratio of chocolate glazed to plain glazed
Mathematics
2 answers:
Ainat [17]2 years ago
6 0

Answer:

7:13

Step-by-step explanation:

That's the simplest form since they're both prime numbers.

Oksanka [162]2 years ago
5 0

Answer:

13:5, or 13 to 5.

Step-by-step explanation:

The 13-to-5 expression can be useful when answering questions about the ratio.

You might be interested in
the maximum distance D in kilometers that you can see from a height H in meters is given by the formula d equals 3.5 times the s
Irina-Kira [14]
First put the words in an algebraic format or a model. D = 3.5(√H). Now determine what the question is asking. It's height. Plug in the value of D. Distance is 35 km.
35 = 3.5(√H) We want to get H by itself. First thing to get away from it is 3.5. So                      divide 35 by 3.5 And 3.5(√h) by 3.5.
10 = √H        To get rid of √ do the opposite raise to the power of 2
10² = (√H)²   
100 = H 
You must be 100 kilometers above ground to see 35 kilometers

7 0
3 years ago
The sum of the first four terms of an arithmetic sequence is $10$. If the fifth term is $5$, what is the sixth term?
Nookie1986 [14]

The sixth term of an arithmetic sequence is 6

<h3>How to find arithmetic sequence?</h3>

The sum of the first four terms of an arithmetic sequence is 10.

The fifth term is 5.

Therefore,

sum of term = n / 2(2a + (n - 1)d)

where

  • a = first term
  • d = common difference
  • n = number of terms

Therefore,

n = 4

10 = 4 / 2 (2a + 3d)

10 = 2(2a + 3d)

10 = 4a + 6d

4a + 6d = 10

a + 4d = 5

4a + 6d = 10

4a + 16d = 20

10d = 10

d = 1

a + 4(1) = 5

a = 1

Therefore,

6th term = a + 5d

6th term = 1 + 5(1)

6th term = 6

learn more on sequence here: brainly.com/question/24128922

#SPJ1

7 0
1 year ago
What is the effect on the area of a rectangle if the dimensions are doubled?
alisha [4.7K]
Let x be the length and y be the width of a rectangle.
Area = xy

When x and y are doubled
Length = 2x and Width = 2y
Area = 2x x 2y
Area = 4xy

-------------------------------------------------------------------------------------------------
Answer: When the dimension is doubled, the area is 4 times the original.
-------------------------------------------------------------------------------------------------
8 0
3 years ago
What are the x and y intercepts of this problem y=-3/8x-9
likoan [24]

Answer:

y=-3/8.0-9 y=1/3 y intercept and for the x intercept is zero

Step-by-step explanation:

3 0
3 years ago
Someone please be awesome and help me please :(
solong [7]

Answer:

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Step-by-step explanation:

x^2+\frac{b}{a}x+\frac{c}{a}=0

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared.  Whatever you add in, you must take out.

x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

Now we are read to write that one part (the first three terms together) as a square:

(x+\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

I don't see this but what happens if we find a common denominator for those 2 terms after the square.  (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0

They put it in ( )

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

I'm going to go ahead and combine those fractions now:

(x+\frac{b}{2a})^2+(\frac{-b^2+4ac}{4a^2})=0

I'm going to factor out a -1 in the second term ( the one in the second ( ) ):

(x+\frac{b}{2a})^2-(\frac{b^2-4ac}{4a^2})=0

Now I'm going to add (b^2-4ac)/(4a^2) on both sides:

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

I'm going to square root both sides to rid of the square on the x+b/(2a) part:

x+\frac{b}{2a}=\pm \sqrt{\frac{b^2-4ac}{4a^2}}

x+\frac{b}{2a}=\pm \frac{\sqrt{b^2-4ac}}{2a}

Now subtract b/(2a) on both sides:

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Combine the fractions (they have the same denominator):

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

6 0
3 years ago
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