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Illusion [34]
3 years ago
12

Which is the simplified form of the expression (StartFraction (2 Superscript negative 3 Baseline) (x Superscript negative 3 Base

line) (y squared) Over (4 Superscript negative 2 Baseline) (x Superscript 4 Baseline) (y Superscript 6 Baseline) EndFraction) Squared? StartFraction 1 Over 4 x squared y Superscript 16 Baseline EndFraction StartFraction 4 Over x squared y Superscript 16 Baseline EndFraction StartFraction 1 Over 4 x Superscript 14 y Superscript 8 Baseline EndFraction StartFraction 4 Over x Superscript 14 Baseline y Superscript 8 Baseline EndFraction
Mathematics
2 answers:
Alexxx [7]3 years ago
8 0

D) 4/x^14 y^8

I just took the quiz on edge

Rama09 [41]3 years ago
4 0

Answer: \frac{4}{x^{14} y^{8}}

Step-by-step explanation:

We have the following expression:

(\frac{2^{-3} x^{-3} y^{2}}{4^{-2} x^{4} y^{6}})^{2}

First, we have to solve what is inside the parenthesis, taking into account the addition and substraction of exponents with the same base:

(\frac{4^{2} y^{2}}{2^{3}x^{4} x^{3} y^{6}})^{2}

(\frac{16}{8 x^{7} y^{4} })^{2}=(\frac{2}{x^{7} y^{4} })^{2}

Finally:

\frac{4}{x^{14} y^{8}}

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Prove that : sinA/1+cosA + 1+cosA/sinA=2cosecA​
tekilochka [14]

Step-by-step explanation:

\frac{sinA}{1+cosA} +\frac{1+cos}{sinA} =2cosec\\\\\\\frac{sin^{2}A+(1+cos)^{2}  }{sinA(1+cosA)} \\\\

\frac{sin^{2}A+1+cos^{2}+2cos}{sinA(1+cosA)} \\\\ and we have sin^{2}+cos^{2} =1

so \frac{1+1+2cosA  }{sinA(1+cosA)} \\\\

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3 0
3 years ago
Help Pleasee<br><br> Reflect shape A in the line x = -2
Cerrena [4.2K]

Answer: Check out the diagram below

The reflected image is shown in red.

=================================================

Explanation:

Draw a vertical line through -2 on the x axis. This is the mirror line.

Now focus on the upper right corner of the figure, which is at (-3, -1). Notice how the horizontal distance from this corner point to the mirror line is exactly 1 unit. If we move another 1 unit to the right, then we'll arrive at (-1,-1) which is where the reflected point lands or ends up.

In short, the upper right corner point (-3,-1) reflects over x = -2 to land on (-1,-1)

----------------------

As another example, the upper left corner point (-5, -1) will move exactly 4 spaces to the right to get to the mirror line. Then we move another 4 spaces to the right to get to (2,-1).

So the upper left corner (-5,-1) will ultimately move to (2,-1) after the reflection over x = -2.

Apply these steps to the other corner points and you'll end up with what is shown below.

Take note that a point like A(-5,-1) moves to A'(1,-1), and similar to the other points as well. Also, notice that when going from A to B to C, etc we are moving clockwise. We move counterclockwise when going from A' to B' to C' etc. Reflections always swap the orientation.

4 0
3 years ago
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Answer:

14.5 feet

Step-by-step explanation:

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