The answer will be z because u can dance and take the L on black kids
The interactions of the ecosystems are all part of the biosphere. The organisms in the biosphere interact with each of the other abiotic physical systems, namely the hydrosphere, the atmosphere and the lithosphere. These interactions not only shape the nature of the ecosystems, but also affect the geology and geography of the system.
Answer:
Explanation:
all the fresh water on the earth are present only in 3 percentage,in the form of glaciers and ice capes.so if this ice melts then they get mixed with the salty water.which will result in the of depletion of the fresh water present on the earth.
<span>In Drosophila + indicates wild-type allele for any gene, m is mahogany and e is ebony.
Female parents are m+/m+ and males are +e/+e.
F1 are m+/+e, all wild type. F1 females are crossed with me/me males - the test cross.
Offspring will be : non recombinant m+/me, mahogany wild type or +e/me wild type ebony. OR
recombinant me/me mahogany ebony or ++/++ wild type.
As the two genes are 25 map units apart, the percentage of recombinants will be 25% and therefore percentage parental types will be 75%.
75% 1000 is 750. There are two parental types, so you would expect 375 of each. Therefore, you would expect 375 m+/me and 375 +e/me.
25% of 1000 is 250 split between two recombinants =125 of each. Therefore you would expect 135 me/me and 125 ++/++</span>
Answer:
3/16
Explanation:
Given,
Black coat color is dominant over brown coat color.
Long mane is dominant over short mane.
BBLL X bbll =
F1: BbLl = Entire progeny has black color and long mane
BbLl progeny will produce BL, Bl, bL and bl gametes. When they interbreed, the resultant F2 progeny will be in 9:3:3:1 dihybrid ratio. Hence in F2,
BBLL : BbLL : bbLl : bbll = 9 : 3 : 3 : 1
3/16 progeny will have bbLl genotype hence 3/16 progeny will have brown, long mane.
